numbers = (38, 35, 28, 46, 92, 75, 49, 76, 81, 69) Partition (numbers, 4, 9) is called. Assume quicksort always chooses the element at the midpoint as the pivot. What is the pivot? Ex: 9 What is the low partition? Ex: 1, 2, 3 (comma between values) What is the high partition? What is numbers after Partition(numbers, 4, 9) completes? (
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Also, can someone explain in simplest detail how to sort when it come to low and high partitioning on the side????
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- 1. a JFrame objects content panel is a(n)________ of type _________ A. object; container B. object; JPanel C. primitive; int D. primitive; double E. none of the above 2. You have a large array that you want to be sorted In ascending order. Under what circumstances would the bubblesort algorithm sort that array very quickly? A. if the array is initially in descending order B. if the array elements can be mapped to a linked list C. if the array elements are already close to their eventual sorted position D. if the array elements are string objects E. never, heapsort will always be fasterPython Can you explain the code with comments? class linkedList(): class _Node: def __init__(self, value, next = None): self._data = value self._next = next def get_data(self): return self._data def set_data(self, value): self._data = value def get_next(self): return self._next def set_next(self, nodetopoint = None): self._next = nodetopoint def __init__(self): self.head = None self.size = 0 def insertNode(self, pos, value): # Add a new node with data set to the value parameter at position pos of list. The first item is at position 0. When pos > size, insert at the end of the list. ####################################################################### # Remove the pass statement and write your code ####################################################################### pass def deleteValue(self, value):…assume you have a HashMap class that uses a threshold of 0.75 (75%),regardless of the collision resolution mechanism used, and has an initial array size of 13. You may assume the array is resized when the current item to be added will make the load factor greater than or equal to the threshold. Recall that the load factor is the fraction of a hash map that is full. If the array is to be resized, assume the array doubles in size and adds one (2 * size + 1).Table 1 contains a list of items and their associated hash codes that were computed with somehypothetical hash function. Assume the items are added to a newly created instance of the HashMap class in the same order in which they are listed in the table. Based on this information, show what the array of the HashMap would look like after all the items have been added using both of the followinghash collision resolution techniques.1. Separate chaining2. linear probingProvide 2 arrays(one for each problem). One that uses separate…
- assume you have a HashMap class that uses a threshold of 0.75 (75%),regardless of the collision resolution mechanism used, and has an initial array size of 13. You may assume the array is resized when the current item to be added will make the load factor greater than or equal to the threshold. Recall that the load factor is the fraction of a hash map that is full. If the array is to be resized, assume the array doubles in size and adds one (2 * size + 1).Table 1 contains a list of items and their associated hash codes that were computed with somehypothetical hash function. Assume the items are added to a newly created instance of the HashMap class in the same order in which they are listed in the table. Based on this information, show what the array of the HashMap would look like after all the items have been added using both of the followinghash collision resolution techniques.1. Separate chaining2. linear probingProvide 2 arrays(one for each problem). One that uses separate…import requestsfrom bs4 import BeautifulSoupimport pandas as pd # Prompt user to enter URLs to scrapeurls = input("Enter URLs to scrape (comma-separated): ").split(",") # Create an empty list to store scraped datadata = [] # Loop through each URL and scrape relevant datafor url in urls:response = requests.get(url)soup = BeautifulSoup(response.content, "html.parser")# Extract relevant data from HTML using BeautifulSoup# In this example, we extract all the links in the HTMLlinks = [link.get("href") for link in soup.find_all("a")]# Append the scraped data to the listdata.append(links) # Create a pandas DataFrame from the scraped data, if the list is not emptyif data:df = pd.DataFrame(data)# Write the DataFrame to an Excel filedf.to_excel("scraped_data.xlsx", index=False)else:print("No URLs entered. Exiting program.") I keep running into a syntax error, could you help me edit this program. I am trying to create a webscraper that asks user to enter a website and then it will put the…The programming language is Python Instructions: Create a function that will delete a node in a Linked List based on position number. On below example, if you want to delete position #2, it will remove the Banana (arrangement of nodes below is Apple, Banana, Cherry, Grapes, Orange). myLinkedList = LinkedList() myLinkedList.append("Banana") myLinkedList.append("Cherry") myLinkedList.append("Grapes") myLinkedList.append("Orange") myLinkedList.prepend("Apple") myLinkedList.deleteByPositionNum(2) node = myLinkedList.head while node: print(node.value, " ") node = node.next_node You may start with the function head:def deleteByPositionNum(self, positionNum):
- create a script that prompts the user for a number. then create a loop to generate that number of random hash tables. then add these hash tables to an array. powershellIn java Create a hash table using an array with elements 324,221,563,679,234,569,890,5678,654 then perform the following operations. 1) Insert 227 2) Delete 679 and Insert 9 3) Insert 67 4) Display the hash table content Note: This hash table uses technique linear probing when encounters a collision.Draw the Weighted Quick Union object on 0 through 10, that results from the following connectconnectcalls. Do not use path compression. Note that if we connect two sets of equal weight, by convention we make the set whose root has a smaller number the parent of the other. We use the convention that if an element is the root of the set, its array value is the weight of the set negated. connect(0, 1); connect(2, 3); connect(9, 5); connect(5, 7); connect(7, 1); connect(4, 2); connect(3, 1);
- Question 3 Design a class of BloomFilter using Python. Please use MurmurHash3 as the hash function and the bitarray Links to an external site.as the bit array. Please also provide at least one test case, i.e., checking the existence of an item in your designed BloomFilter. Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this linethere is a problem with this code I want to delete node 10 and display the linked list after that it cannot be displayed and I don't know why please don't change the type of node from class to struct the code : #include <iostream>using namespace std; class node{public: int data; node* next;}; void display(node * head) // printing the data of the nodes{ node* temp = head; while (temp != NULL) { cout << temp->data << endl; temp = temp->next; }} // add void push(node** head, int newdata) // { 5, 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = *head; *head = newnode;} void append(node** head, int newdata) // { 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = NULL; node* last = *head; if (*head == NULL) { *head = newnode;…Below is a memory diagram of a LinkedIntList object. Which of the code fragments below the diagram would insert the number 50 between the 11 and 12? Node newNode = new Node();newNode.item = 50;newNode.next = first;first = newNode; Node newNode = new Node();newNode.item = 50;newNode.next = first.next.next;first.next = newNode; Node newNode = new Node();newNode.item = 50;newNode.next = first.next;first.next = newNode; Node newNode = new Node();newNode.item = 50;newNode.next = null;first.next.next = newNode;