nvobability density function (pdf) isHow did he get thevalue inside the circle?unda probability d.4 is umtyAYeaPCx)dx->14.1-x1dr =1e?dx +e de「cス]°.+ (cas 1-x111-0:018) t [s4.6-) =0.982.+53.6%3D1/kK. =54582K : O'O183トーa)Step $izeXmax - Xmin%3Dho of Levels4+4Ştep sizc =

Answered: Image /qna-images/answer/c01dc644-7f1d-44e5-a39f-5b3002cae1a9.jpg

nvobability density fonction (pdf) How did he get the value inside the circle? unda probability d-f iş unity AYea PCx)dx 1 -4 |-x| dr =1 edx + t. as 1-21-n ! %3D 11-0:018) t [s4.6-= 0.982.+ 53.6 %3D 1/k 54.582 K : O'O183 8 ナ

nvobability density fonction (pdf) How did he get the value inside the circle? unda probability d-f iş unity AYea PCx)dx 1 -4 |-x| dr =1 edx + t. as 1-21-n ! %3D 11-0:018) t [s4.6-= 0.982.+ 53.6 %3D 1/k 54.582 K : O'O183 8 ナ

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter1: Functions

Section1.2: Functions Given By Tables

Problem 11E: A Troublesome Snowball One winter afternoon, unbeknownst to his mom, a child bring a snowball into...

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Question

nvobability density function (pdf) is
How did he get the
value inside the circle?
unda probability d.4 is umty
AYea
PCx)dx
->
14.1-x1
dr =1
e?dx +
e de
「cス]°.
+ (c
as 1-x1
11-0:018) t [s4.6-) =
0.982.+
53.6
%3D
1/k
K. =
54582
K : O'O183
トー
a)
Step $ize
Xmax - Xmin
%3D
ho of Levels
4+4
Ştep sizc =

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