↑ nyList Bob } O void mystery(node* & ptr) { Consider the figure and function shown below: Show the configuration of the list after mystery(myList) is executed. ▪ In general, how does this function transform such a singly linked structure? Node } node *tmpPtr; while (ptr) { tmpPtr = ptr; if (tmpPtr->next) { Vic } ptr = ptr->next; Bob tmpPtr = tmpPtr->next; ptr->next = tmpPtr->next; delete tmpPtr; next Sam Joy

↑ nyList Bob } O void mystery(node* & ptr) { Consider the figure and function shown below: Show the configuration of the list after mystery(myList) is executed. ▪ In general, how does this function transform such a singly linked structure? Node } node *tmpPtr; while (ptr) { tmpPtr = ptr; if (tmpPtr->next) { Vic } ptr = ptr->next; Bob tmpPtr = tmpPtr->next; ptr->next = tmpPtr->next; delete tmpPtr; next Sam Joy

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This code by C to : Create a sorted linked list using tenStudent array (copy from array into the linked list will be done). and Details in the picture: >>>>>>>>>>>>>>>>>>>>>>> by Using the linked list which is populated (The above-mentioned), create a binary tree. The new tree will be created during the deletion of the linked list. The code: #include<stdio.h> struct student{int TC;char F_name[12];char L_name[12];int age;char gender[2];}; struct Linked_list_node{struct student info;struct node* next;}; struct student tenStudent[10] = {123,"X1","Y1",21,"M",234,"X2","Y2",26,"F",128,"X3","Y3",18,"M",432,"X4","Y4",27,"M",287,"X5","Y5",34,"F",423,"X6","Y6",21,"M",634,"X7","Y7",16,"F",828,"X8","Y8",15,"M",252,"X9","Y9",27,"F",887,"X10","Y10",34,"F",}; int main(){//create a head node for linked liststruct Linked_list_node* head = (struct Linked_list_node*)malloc(sizeof(struct Linked_list_node));//add first student to…
How nodes are defined (struct node (value count left right) #:mutable #:transparent) Write in Racket (traverse n) A traversal of a BST is an algorithm for “visiting” all node in the BST. The traversal must visit each node exactly once. In the case of a linked list, a traversal is trivial since the structure is linear: start at the head, move to the next node, and stop when you reach the tail. In the case of a BST, traversal must account for multiple child nodes and keep track of which subtrees have already been visited and which have not. There are three types of traversal: in-order, pre-order, and post-order. We will only implement in-order. The in-order traversal of a BST has the property that the node values will display in ascending or sorted order. The function can be defined either recursively or iteratively. Recursion is much simpler, so we’ll stick to that. Recursive Algorithm for In-Order Traversal of BST parameter: node n, the root of the tree…
Please make a JAVA code for the following: Use a singly-linked node class to implement the linked list implementation. Details of the Node class to be used are as follows.
void doo(node<int>*root){ if(root !=0) { node<int>*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do? a. swap the first item with the last item in the linked list b. doesn't do anything because the root parameter is passed by value c. set the first item in the linked list as the last item d. change the root item in the binary tree with the farthest leaf item
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