O a. If F(X,Y)=F(X)F(Y), it is not necessarily true that p(XY)=p(X)p(Y) O b. If p(XY)=p(X)p(Y), then E[XY] = E[X]E[Y] O c. If E[XY] = E[X]E[Y], then X and Y are independent O d. If E[X+Y]=E[X]+E[Y], then F(X,Y)=F(X)F(Y) O e. If Cov(X,Y)=0, then p(XY)=p(X)p(Y)
O a. If F(X,Y)=F(X)F(Y), it is not necessarily true that p(XY)=p(X)p(Y) O b. If p(XY)=p(X)p(Y), then E[XY] = E[X]E[Y] O c. If E[XY] = E[X]E[Y], then X and Y are independent O d. If E[X+Y]=E[X]+E[Y], then F(X,Y)=F(X)F(Y) O e. If Cov(X,Y)=0, then p(XY)=p(X)p(Y)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Select the statement(s) that is(are) correct regarding random variables X and Y:
![O a. If F(X,Y)=F(X)F(Y), it is not necessarily true that p(XY)=p(X)p(Y)
O b. If p(XY)=p(X)p(Y), then E[XY] = E[X]E[Y]
O c. If E[XY] = E[X]E[Y], then X and Y are independent
O d. If E[X+Y]=E[X]+E[Y], then F(X,Y)=F(X)F(Y)
O e. If Cov(X,Y)=0, then p(XY)=p(X)p(Y)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd3be9fc5-49dc-4987-93dc-30b0d6519ab7%2F81311c3a-a8ae-43e3-bf55-ef88d87a529f%2Fa0wusig_processed.png&w=3840&q=75)
Transcribed Image Text:O a. If F(X,Y)=F(X)F(Y), it is not necessarily true that p(XY)=p(X)p(Y)
O b. If p(XY)=p(X)p(Y), then E[XY] = E[X]E[Y]
O c. If E[XY] = E[X]E[Y], then X and Y are independent
O d. If E[X+Y]=E[X]+E[Y], then F(X,Y)=F(X)F(Y)
O e. If Cov(X,Y)=0, then p(XY)=p(X)p(Y)
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