O EXAMPLE 2 For the region under f(x) 2x on [0, 2), show that the sum of the areas of the upper 16 approximating rectangle approaches that is 16 lim R 3.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Author:Bruce Crauder, Benny Evans, Alan Noell
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ChapterA: Appendix
SectionA.2: Geometric Constructions
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O EXAMPLE 2 For the region under f(x) = 2x2 on [0, 2], show that the sum of the areas of the upper
approximating rectangle approaches
that is
(2, 8)
16
lim R, =
3
SOLUTION Re is the sum of the areas of the n rectangles in the figure. Each rectangle has width
and the
2n
heights are the values of
the function f(x) = 2x2 at the points 2 1 6
n'n
that is, the heights are
Thus,
R, = -
· (12 + 22 + 3? +. .. + n²).
(12 + 22 + 32 +... + n).
1/n
Video Example
Here we need the formula for the sum of the squares of the firstn positive integers:
n(n + 1)(2n + 1)
12 + 22 + 32 +... + n2
6
Perhaps you have seen this formula before. Putting this formula into our expression for Rn, we get
n(n + 1)(2n + 1
Transcribed Image Text:O EXAMPLE 2 For the region under f(x) = 2x2 on [0, 2], show that the sum of the areas of the upper approximating rectangle approaches that is (2, 8) 16 lim R, = 3 SOLUTION Re is the sum of the areas of the n rectangles in the figure. Each rectangle has width and the 2n heights are the values of the function f(x) = 2x2 at the points 2 1 6 n'n that is, the heights are Thus, R, = - · (12 + 22 + 3? +. .. + n²). (12 + 22 + 32 +... + n). 1/n Video Example Here we need the formula for the sum of the squares of the firstn positive integers: n(n + 1)(2n + 1) 12 + 22 + 32 +... + n2 6 Perhaps you have seen this formula before. Putting this formula into our expression for Rn, we get n(n + 1)(2n + 1
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