Consider the following.Rewrite the integralof (x - 19)OO[³x³ dxOOdx = 960,(x-19[₁cx.√₁² (x-(x - 19) dx = 19- 19) dx =(x - 19) dx in terms of the given integrals.19 [" (x) dx - frº dx["x dx = 24, ["dx = 4[(x) dx - 19 [* dx(x - 19) dx = 19(x - 19) dx =- 19 [° (x²³) dx - ["(x) dx - [* dxax(x - 19) dx == ["(x) dx + 19 [* dx√(x - 19- 1" (x ³) dx - 19 [* dxEvaluate the integral using the given values.(x - 19) dx =

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O Rewrite the integral ["x³ dx = 960, ["x dx = 24, ["dx = 4 f(x - 19) O √₁ (x-1 O 1₁° Cx (x - 19) dx in terms of the given integrals. (x19) dx = 19 (x - 19) dx = 8 19 [° (x) dx - [° dx fx-15 o f(x - 19). O (x19) dx = 19 8 ["(x) dx - 19 ["dx - 19 [ * (x³) dx - ["(x) dx - [" dx Lx ax Lax (x - 19) dx = (x - 19) dx = - [* (x) dx + 19 [* dx [Ⓡ (x - 19) dx = <- [* (x³) dx - 19 ºdx Evaluate the integral using the given values. Loc

O Rewrite the integral ["x³ dx = 960, ["x dx = 24, ["dx = 4 f(x - 19) O √₁ (x-1 O 1₁° Cx (x - 19) dx in terms of the given integrals. (x19) dx = 19 (x - 19) dx = 8 19 [° (x) dx - [° dx fx-15 o f(x - 19). O (x19) dx = 19 8 ["(x) dx - 19 ["dx - 19 [ * (x³) dx - ["(x) dx - [" dx Lx ax Lax (x - 19) dx = (x - 19) dx = - [* (x) dx + 19 [* dx [Ⓡ (x - 19) dx = <- [* (x³) dx - 19 ºdx Evaluate the integral using the given values. Loc

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter7: Integration

Section7.2: Substitution

Problem 18E: Use substitution to find each indefinite integral. 4xx2+3dx

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