Type Casting & Inspection - How do you do this with Swift code? Create a variable total of type Double set to 0. Then loop through the dictionary, and add the value of each integer and double to your variable's value. For each string value, add 1 to thetotal. For each boolean, add 2 to the total if the boolean is true, or subtract 3 if it's false. Print the value of total.Create a variable total2 of type Double set to 0. Loop through the collection again, adding up all the integers and doubles. For each string that you come across during the loop, attemptto convert the string into a number, and add that value to the total. Ignore booleans. Print the total.

Step 1 : Start Step 2 : Create a collection of Type : Any and Initialize it with some values of type…

Answered: o this with Swift cod

Engineering

Computer Science

o this with Swift cod

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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import are as are# A dictionary for the simplified dragon text game# The dictionary links a room to other rooms.rooms = {'Great Hall': {'South': 'Bedroom'},'Bedroom': {'North': 'Great Hall', 'East': 'Cellar'},'Cellar': {'West': 'Bedroom'}}location = 'Great Hall' # set starting room# Based on the start room (a key), what is the corresponding dictionary value?print("\n", rooms[location])# Available directionsprint(rooms[location].keys())print(*rooms[location].keys())# Available roomsprint(rooms[location].values())print(*rooms[location].values())direction = ['South', 'North', 'East', 'West']# game loopwhile direction != "exit":print('\nYou are in the',location)possible_moves = rooms[location].keys()print('possible moves', *possible_moves)direction = input("Which direction should I go?").strip().lower()print('You chose to go:', direction)I am supposed to make a program to be able to move from room to room in python, and exit, how do I finish this is as far as I have completed
Write a way to turn one word into another using just one letter at a time, given two words of equal length from a dictionary. Each new term you create must be in the dictionary.EXAMPLEDAMP, LIKE as inputDAMP-> LAMP-> LIMP-> LIME-> LIKE is the output.
From two dictionary objects created in the codes below, find letters that only exist in one of the dictionaries. Use a SET object(s) and its mathematical operator(s). import string # import string library import random # import random library # a_base is a string containing concatenation of letters s_base = string.ascii_letters # random.seed() accepts any integer to initialize random numbers random.seed(582) # s is a string variable s = "" # this line creates a loop starting from 0 to 199 for i in range(200): # this line randomly selects letters from s_base variable and concatenates them to the value stored in s s += s_base[random.randint(0, 25)] # this line prints the value of s print(s) # count each char frequency count = {} for ch in s: if ch in count: count[ch] = count[ch]+1 else: count[ch] = 1 # print the frequency for key in count: print("{} -> {}".format(key, count[key])) def char_frequency(s): dict = {} for d in s: keys =…
Try to create a dictionary that has a listing of people and includes one interesting fact about each of them. Display each person and their interesting fact on the screen. From there, alter a fact about one of the people on the list. Also, add an extra person and corresponding fact to the list. Display the newly created list of people and facts. Try running the program multiple times and take note of whether the order changes.
Make a dictionary, the student's name is the key (a string) and the student's test scores is the value (a list). So it should be a dictionary with six key value pairs in it. Here is data to use. Brian,94,89,92 Rachel,100,90,65 Jon,67.5,95,100 Brit,0,78,80 Greg,65,100,78 Andrea,55.5,67,79 1. Now print the dictionary data using a loop that starts with for key, value in. 2. Now print the dictionary data using a loop that starts with for key in 3. Find and print out Rachels second score (should be a 90) 4. This one is a little tricky, a little mind-bender. Make a new dictionary. Using the dictionary you made from above,. the new dictionary should consist of the key is the name of the person, and the value is just the average of their scores. So it’s six key value pairs but instead of the value being a list like the first problems, this time it's just their average (which you compute from their scores in the other dictionary. Print the new dictionary out. 5. You…
Write a python program that asks the user for a range (a starting number(inclusive) and an ending number(inclusive)) and checks the divisibility of all the numbers within that range. Then construct a dictionary with keys “Divisible by 3”, “Divisible by 5”, “Divisible by 7”, and “None”, with values as lists of elements satisfying the respective condition. Finally, print the dictionary.
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Given two words of equal length that are in a dictionary, write a method totransform one word into another word by changing only one letter at a time. The new word you getin each step must be in the dictionary.EXAMPLEInput: DAMP, LIKEOutput: DAMP-> LAMP-> LIMP-> LIME-> LIKE
Consider the dictionary below: student = { "name": "Emma", "class": 9, "marks": 75} Select all the correct methods to obtain the value(s) of the key marks from the dictiona a.) m = student.get(2) b m = student.get('marks') c m = (student[2]) d m = (student['marks']) e none of the above f A and C g B and D
def city_dict(adict): """ Question 6 -Given a dictionary that maps a person to a list of countries they want to travel to, return a dictionary with the value being the list sorted by the last letter in each countries name. If two countries have the same last letter, sort by the first letter. -For an extra challenge, try doing this in one line (Optional). Args: adict (dict) Returns: dict >>> city_dict({"Pablo": ["Belgium", "Canada", "Germany"], "Athena": ["Italy", "France", "Egypt"], "Liv": ["Japan", "Bolivia", "Greece"]}) {'Pablo': ['Canada', 'Belgium', 'Germany'], 'Athena': ['France', 'Egypt', 'Italy'], 'Liv': ['Bolivia', 'Greece', 'Japan']} >>> city_dict({"Jacob": ["Bahamas", "Brazil", "Chile"], "Lexi": ["Colombia", "Finland", "Panama"], "Emily": ["Ireland", "Russia", "Kenya", "Jordan"]}) {'Jacob': ['Chile', 'Brazil', 'Bahamas'], 'Lexi': ['Colombia', 'Panama', 'Finland'], 'Emily': ['Kenya',…
Using Python, write a program which opens a text file and loads the data into a dictionary where the key is the line # from the file and the value is the line of text from the file. For instance, if the file looks like: Hello,Welcome to Introduction to Big Data It is good to meet everyone.Hope you enjoy the class. The dictionary should look like: KEY VALUE 1 Hello, 2 Welcome to Introduction to Big Data 3 It is good to meet everyone. 4 Hope you enjoy the class. Then change it to a list and reverse the order of the lines of text and save it back to a new text file.
In JAVA, use a HashMap to count and store the frequency counts for all the words from a large text document. Using file util, please. Then, display the contents of this HashMap with words and frequency count. Next, please create a set view of the Map and store the contents in an array. Sort this array based on key value and display it. Finally, sort the array in decreasing order by frequency and display it as well. Please label your explanation in the code Thank you