Object: Square States: side Behaviors: computeArea(), computePerimeter() Object: RightTriangle States: base, height Behaviors: computeArea(), computePerimeter() - Find first the hypotenuse which is the 3rd (longest) side using the Pythagorean formula. You may use the sqrt() method defined in Math Java class
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Object: Square
States: side
Behaviors: computeArea(), computePerimeter()
Object: RightTriangle
States: base, height
Behaviors: computeArea(), computePerimeter() -
Find first the hypotenuse which is the 3rd (longest) side using the Pythagorean formula. You may use the sqrt() method defined in Math Java class
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- There are several techniques for implementingthe sqrt method in the Math class. One such technique is known as theBabylonian method. It approximates the square root of a number, n, by repeatedlyperforming the calculation using the following formula:nextGuess = (lastGuess + n / lastGuess) / 2When nextGuess and lastGuess are almost identical, nextGuess is theapproximated square root. The initial guess can be any positive value (e.g., 1).This value will be the starting value for lastGuess. If the difference betweennextGuess and lastGuess is less than a very small number, such as 0.0001,you can claim that nextGuess is the approximated square root of n. If not, nextGuessbecomes lastGuess and the approximation process continues. Implementthe following method that returns the square root of n:public static double sqrt(long n)Java Programming. Needs to be done with loops. Define a public static method called printPyramid(). This method should have publicstatic as its visibility modifiers. It should not return a value. It has a single integer parameter.When printPyramid() is called with an integer value, it should print a pyramid with a heightof that value.For example, if we call printPyramid() with an integer value of 5, then the following shouldbe displayed in the output console.** ** * ** * * ** * * * *You will have to use multiple for loops (consider nested for loops) to write this method.❏ In your main method, you should ask the user for the desired height of the pyramid. The usershould provide a value greater than 1. If the user does not provide a valid value, you should forcethe user to continue entering values until they enter a correct one.Then, call the printPyramid() method with the height given by the user.A regular polygon is an n-sided polygonin which all sides are of the same length and all angles have the same degree (i.e.,the polygon is both equilateral and equiangular). The formula for computing thearea of a regular polygon is given below: Write a method that returns the area of a regular polygon using the following header:public static double area(int n, double side)Write a main method that prompts the user to enter the number of sides and theside of a regular polygon and displays its area. Here is a sample run: Enter the number of sides: 5 ↵EnterEnter the side: 6.5 ↵EnterThe area of the polygon is 72.69017017488385
- Nancy wants to hang a photo frame of her graduation photo. The ladder is placed at 2 feet away from the wall. The angle that is formed by the wall and the ground is 105 degrees and the angle formed by the center mark and the ladder will be 15 degrees. In Java programming context, use the predefined method(s) in Math class, find the length of the ladder (in 2 decimal format) that Nancy needed in order to put up her graduation photo neatlyHere's the problem " (Math: approximate the square root) There are several techniques for implementingthe sqrt method in the Math class. One such technique is known as theBabylonian method. It approximates the square root of a number, n, by repeatedlyperforming a calculation using the following formula: nextGuess = (lastGuess + n / lastGuess) / 2 When nextGuess and lastGuess are almost identical, nextGuess is theapproximated square root. The initial guess can be any positive value (e.g., 1).This value will be the starting value for lastGuess. If the difference betweennextGuess and lastGuess is less than a very small number, such as 0.0001,you can claim that nextGuess is the approximated square root of n. If not, next-Guess becomes lastGuess and the approximation process continues. Implementthe following method that returns the square root of n.public static double sqrt(long n)" I have my java code here " import java.util.Scanner;public class Main2 {public static void main(String[]…Please make a JAVA PROGRAM of this problem (See attached photos below) Program it simple if possible Topic: Java EssentialsFLAMES GAME Implement the method interface Flames in has the following methods: public int countLetters(String name1, String name2);- this method returns the total leftover letters between name1 and name2 public char flames(int numLetters);- this method returns the letter equivalent to the numLetters - example if numLetters is 10 is will return the letter 'M' public String letterEquivalent(char flames);-returns the String equivalent of variable flames. Below is the reference for the variable flames F - Friends L - Lovers A - Affectionate M - Marriage E - Enemies S - Sweethearts
- Question:Write the method in java for following a)Method returns a translated pointb) Method returns a rotated point w.r.t pivot pointc) Method receives a Target point, Pivot point, Translation Factors and Angle in Degree, and it return a Point which is translated and rotated (Sequence is T->R). Must use methods of a and b.Please help to solve this codes. In Java public interface ShapesInterface{ public double getArea(); // This method returns the area of a 2 dimensional shape // or the surface are of a 3 dimensional shape. public double getVolume(); // This method returns the volume of a 3 dimensional shape // or 0 for a 2 dimensional shape. public void displayArea(); // This method displays the name of the shape and its area, // If the shape is 2 dimensional it displays the 2 dimensional area // If the shape is 3 dimensional it displays the surface area of the shape public void displayVolume(); // This method displays the name of the shape and its volume, // This method displays the volume of a 3 dimensional shape and 0 for a 2 dimensional shape. }In geometry, polygons are defined as plane (two-dimensional) and closed shapes that are formedby three or more straight lines joined with each other. Write a java program to develop an OOPsolution presenting a regular polygon object. A regular polygon has a name, n number of sideswith the same length. The perimeter of a regular polygon can be found by computing the totallength of all n sides. A polygon can be a triangle that also has a height value.Create the following classes and interface:A. Interface Geometry includes a single method called perimeter() that returns a doublevalue presenting the perimeter of a shape.B. Implement class Polygon as follows: Include the required instance variables as described above, and a constructor method witharguments. Add two get methods to return number of sides and value of side length. Implement the method perimeter() from the Geometry interface as the perimetervalue of a polygon. Implement area() method that returns value 0.0; Override…
- Please answer the question posted and give full explanation of the answer. Please past the successful program run as well. Please ensure to write two separate programs for Geometry.java and Geometrytest.java. Please remember to put your name and date of program completion in a comment at the top of your .java files. Design a Geometry class (Geometry.java) with the following methods: A static method that accepts the radius of a circle and returns the area of the circle. Use the following formula: Area = πr2 Use Math.PI for π and the radius of the circle for r. A static method that accepts the length and width of a rectangle and returns the area of the rectangle. Use the following formula: Area = Length x Width A static method that accepts the length of a triangle’s base and the triangle’s height. The method should return the area of the triangle. Use the following formula: Area = Base x Height x 0.5 The methods should display an error message if negative values are used…Basic Java please Write a method called torusVolume(? littleR, ? bigR) that takes an int littleR and an int bigR in as parameters. Use the two values to find and return the volume as a double of the associated regular octagonal prism. The formula for the volume of a torus is (2πR)⋅(πr^2)Given the Solid class, extend it with: Pyramid Cylinder RectangularPrism Sphere Make sure to create the constructor and override the volume and surfaceArea methods. Also extend RectangularPrism with Cube. HINT: You can look up formulas for how to compute the volume and surface area of a certain type of shape online. ========================================== public class SolidTester{public static void main(String[] args){String name;double volume;double surfaceArea; // Pyramid constructor should take name, length, width, height// in that orderPyramid pyramid = new Pyramid("My pyramid", 1, 3, 5);name = pyramid.getName();volume = round(pyramid.volume(), 2);surfaceArea = round(pyramid.surfaceArea(), 2);System.out.println("Pyramid '" + name + "' has volume: " + volume +" and surface area: " + surfaceArea + "."); // Sphere constructor should take name then radiusSphere sphere = new Sphere("My sphere", 4);name = sphere.getName();volume = round(sphere.volume(), 2);surfaceArea =…