Complete the tableBearing or Azimuth of Line AB: N 55°57' EObserved Interior Angle eReversed MeanAdjustedCorr InteriorAngleStaStaDistMeanОссObs(m)DistDirect11.55A103°22' 102°57'В13.20A13.20В88°14'88°14'17.42В17.42113°36'| 112°48'D10.0010.00156°06'154°31'13.90D13.9081°42'81°42'A11.55

The mean distance and the mean included interior angles are calculated by taking the average of the…

Observed Interior Angle e Reversed Mean Adjusted Corr Interior Angle Sta Sta Dist Мean Oc Obs (m) Dist Direct E 11.55 A 103°22' 102°57' В 13.20 A 13.20 В 88°14' 88°14' 17.42 В 17.42 113°36' 112°48' D 10.00 10.00 156°06' 154°31' E 13.90 D 13.90 81°42' 81°42' A 11.55

Observed Interior Angle e Reversed Mean Adjusted Corr Interior Angle Sta Sta Dist Мean Oc Obs (m) Dist Direct E 11.55 A 103°22' 102°57' В 13.20 A 13.20 В 88°14' 88°14' 17.42 В 17.42 113°36' 112°48' D 10.00 10.00 156°06' 154°31' E 13.90 D 13.90 81°42' 81°42' A 11.55

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A transit with stadia interval factor of 100.8 was set up at point C on the line between points A…

Q: The horizontal angles about point P were measured and recorded as follows: <1 = 17 deg 30ʻ10", <2 =…

Q: The readings (2.312, 1.185, -2.365, 0.195, 0.885, 1.345, 0.905) were taken with a level. The…

A: The calculations are shown in tabular form in step 2

Q: 1. Compute and adjust the following set of closed-loop level observations: Pt BS HI FS Elev BM A…

A: To compute and adjust the closed loop level.

Q: Estimate in (m/sec) se= 1572o Pa し-30.48 n = O-000045 M= 0.01 Pa.s 1: 1200

A: step 1-

Q: Surveying The following readings were observed with a dumpy level of 0.795, 1.535, 2.855, 3.125,…

A: Given data; RL of the benchmark= 608.400 Instrument was shifted after, 4th &8th reading;

Q: (c) To determine the elevation of station A, the following observation were taken, the rod held…

A: Elevation diagram of the staff station and instrument stations: Anallatic lens C = 0 K =100

Q: ROD HAIR READINGS POSITION UPPER MIDDLE LOWER Rod held at A 1.327m 1.171m 1.011m Rod held at B…

Q: Station Sight (+) Stadia Sight (-) Stadia Elev. ВМА 510,38 6,920 6,240 5,360 5,470 4,210 4,330 TP1…

Q: Calculate the polar radius of gyration of the shaded area about its centroid C. Assume t=115 mm, a…

Q: Two pegs A and B are driven in the ground at a distance of abour 120 m. A dumpy level is set up at…

A: Introduction- Surveying is heavily reliant on levelling. A dumpy level is a type of levelling tool…

Q: √3=9 P₂=9 P3=9 27 = ? Pi=30 K^ D T √₁-3 D=450mm Ref Axis Z2-5 3 m K 545 за 23=4.5 7 12:2.5 1 2D₂=300…

Q: J) Adjusted bearing on line DA (round to the nearest second ) LINE DISTANCE (m) BEARING АВ 388. 08 S…

A: Signs for Lattitude and Departure: If Bearing is in N-E = Both positive S-E = L -e and D +ve S-W…

Q: A transit with stadia interval factor of 100.8 was set up at point C on the line between points A…

A: Schematic representation of the given figure:

Q: M. and 6:00 P.M. is approximately V= t3 - 10.5t? + 30t + 20 miles per hour where t = number of hours…

A: Given:- v=t3-10.5t2+30t+20 miles per hour t=number of hours past noon To find:- absolute relative…

Q: 3) 100 клу lom 50 куп A

Q: STATION DIRECT DOUBLE MEAN REMARKS DEFL. DEFL. DEFL. Azimuth 111 - 112 = 121° 21' 111 147° 01' 293°…

A: Station Direct Double Mean Remark 111 147°1' 293°59' 147° (147°1'+293°59')/3 112 116°11' 232°22'…

Q: Q/1/..The following staff readings were observed successively with a level. The instrument has…

Q: STATION BS HI FS ELEVATION Sta A |: 25 500. 06 m TP 1 l.24 2.48 TP 2 go18 ТР 3 ト96 2177 TP 4 (. 50…

Q: Find the position of NA if 250*350 mm Ast is 1200 mm sq FE250. M25

A: This problem is related to RCC , Design concrete structure. In this Question given about Width and…

Q: A stadia rod held at point B was observed from station A (elev A = 210.70m) using an automatic…

Q: diagram. 10kN.m 2m 3m (20+#ID)/2 KN 2m 5m 77 5kN/m B

Q: A transit with stadia interval factor of 100.8 was set up at point C on the line between points A…

A: Given :- Stadia interval factor (K) = 100.8 set up at point C between A & B Distance from the…

Q: DETERMINE THE maGniTuOE ano DIRE CTIO OF RES ULTANT OF TW0 FORCES 5kN 650 300

A: Given first force P= 5 kN; Second force Q= 4KN Let resultant of these two forces is R which makes…

Q: Example-3: Following readings were taken with level. 1.155, 1.565, 2.695, 3.580, 2.085, 2.895,…

Q: EL 255m 30m Ground Surface EL. 220m Y= 20KN/m 10m

Q: Bearing or Azimuth of Line AB: Adjusted Interior Sta Dist Observed Interior Angle 0 Sta Obs Мean…

Q: STATION H.I H. ANGLE H. DIST V. DIST ELEV. ft ft ft Instrument station #1 (between BM and station…

A: Height of the instrument =elevation +vertical height and elevation =height of indtrument -vetical…

Q: omplete the table of information and calculate the difference in elevation of ation 0+ 020 and…

A: HERE BS FS AND IS ARE GIVEN .RL IS ALSO GIVEN THATS IS 200

Q: Line Length Pg Up Pg Dn 44 Observed magnetic azimuth Computed magnetic beaning Backward Forward…

Q: transit was set up 30 meters and 80 meters away from point A and B respectively. The rod intercept…

Q: El. 90 m A El. 75 m El. 50 m El. 30 m D Line 3: 45um - 300mm Line 4: 900m - 150mm 600m - 600mm Line…

Q: For the data below find AADT. Time Volume 8:00-9:00 500 9:00-10:00 350 10:00-11:00 200 11:00-12:00…

Q: 0.8 m 643m 15 AN C LOM D VN 120

A: Given Data:UDL=6kN/mConcentrated Load = 15kNSpan =3m

Q: 12.find interval normal moment

A: in above structure there are two hinge joint at S1 and S2 location. as we know, hinge releases all…

Q: KE = 12,000J %3D m = 40kg

Q: A tacheometer is setup at A and the readings on the staff at B are 1.77m, 2.12m, 2.34m and the…

A: Given Data: A Tacheometer setup at A. Staff Readings at B are 1.77m, 2.12m, 2.34m Inclination of…

Q: A transit with stadia interval factor of 100.8 was set up at point C on the line between points A…

A: Given Data: The stadia interval factor is k=100.8. The distance from the instrument to the focus is…

Q: Estimate the missing precipitation of station A by the inverse distance method. STATION COORDINATES…

Q: Find the cam diameter and actual volume displaced? Volumetric efficiency 1420 rpm, e = 14.67 mm, L =…

A: Volumetric efficiency, ηv=91.87%=0.9187 Vane pump speed, N=1420 rpm Eccentricity, e=14.67 mm=0.01467…

Q: he HI of the instrument placed on top of a 50 m high hill is 1.2 m . The top of the water tank…

A: solution Given height of the instrument HI=1.2mts the instrument is placed at elevation of 50mts…

Q: RB 4 RA 30m H A 92 1200 800 400 200

Q: omplete the fieldwork report for this data: STA BS HI FS IFS ELEV Remarks BM-A 0.95 101.345 m 0+000…

A: To complete the fieldwork report

Q: 48.1 VSM RSX 134. 726 Pom sm 2.5m S MS

Q: Two pegs A and B are driven in the ground at a distance of abour 120 m. A dumpy level is set up at…

A: Elevation refers to the vertical distance between one point and the horizon. Elevations are measured…

Q: Find the equal height of towers at triangulation stations A and C so that line AC will clear the…

A: Given, AB = 10 km BC = 8.7 km

Q: A transit with stadia interval factor of 100.8 was set up at point C on the line between points A…

A: Draw the figure.

Q: El. ? El. 90 m El. 90 m 300m - 450 mm f = 0.03 F El. 80 m A 600m - 600 mm f = 0.025 E 300m - 450 mm…

Q: earing or Azimuth of Line AB: 16710' Sta Observed Interior Angle 0 Adjusted Interior Sta Dist Мean…

A: Given: Required to find:

Q: \begin{array}{r}\frac{2}{7} \\\times \frac{49}{50} \\\hline\end{array}

A: Given:- 2/7 and 49/50 To find:- Multiplication

Concept explainers

Instruments for Surveying

Surveying is the practice that determines the relative three-dimensional positions of many different points on the earth’s surface. There are various instruments used in Surveying like Theodolites, Total station, Tripod stands, Plane table, etc. for measuring horizontal angle, vertical and sloping angle, which are very useful for giving accurate and precise measurement.

Question

Complete the table
Bearing or Azimuth of Line AB: N 55°57' E
Observed Interior Angle e
Reversed Mean
Adjusted
Corr Interior
Angle
Sta
Sta
Dist
Mean
Осс
Obs
(m)
Dist
Direct
11.55
A
103°22' 102°57'
В
13.20
A
13.20
В
88°14'
88°14'
17.42
В
17.42
113°36'| 112°48'
D
10.00
10.00
156°06'
154°31'
13.90
D
13.90
81°42'
81°42'
A
11.55

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Check the interior included angle:

VIEW

Step 2: Corrected interior included angles:

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
On the drawing below, the virtual condition of the 4 holes is? O .450 .375 O.395 O .020 D O .430 Ø3.000 .020 0 10 45° 4X Ø.395-.430 Ø.500-.510 Ø.020MABMCM +0.010M ADM Ø2.000 .375-.395 4.000MABM C A 0.005MA B
2. Complete the missing data. LINE DISTANCE (meter) BEARING 1-2 123.4450 140.2336 S 73.45E N 18.19E 2-3 3-4 4-5 146.3536 164.868 S74.21E S 19.71 W S81.90 W N 52.88 W 5-6 6-7 194.7219 7-1 96.3024
2)Given the following set of stadia level notes. FORESIGHT VERTICAL BACKSIGHT STA STADIA VERTICAL STADIA ELEV(m) INTERVAL ANGLE ROD RDG| INTERVAL ANGLE ROD RDG (-)15°º45' (-)18°10' A 1.75 2.1 425.15 (+)12º48' (-)9°18" ТР-1 2.15 1.92 1.55 1.58 В 3.2 1.65 The instrument used was a transit w/ an internal focusing telescope and a stadia interval factor of 98,and all linear measurements are in meters.Determine: a)the difference in elevation between station A and the turning point b)the elevation of TP-1 c)the elevation of station B d)the difference in elevation between sta. A and sta. B
Determine the force of all members using METHOD OF JOINT. Answer in 3 decimal places only. TRUSS MEMBERS ● FORCE COMPRESSION OR TENSION
Q3/ complete (LAT, DEP) of travers ABCDE Station Azimuth Length Latitude Departure A 26 10' 285.10 104 35' 610.45 195 30' 720.48 358 18' 203.00 306 54' 647.02 A Misclosure Q4) Alcomplete the flowing (choose 5) 1 Tempereture Ct = 2_Area of ellipse = 3 Azimutu dic (175 30°) in bearing = 4_The angle (100grad 50 c.grad) in sexagesimel = 5_The angle 30° in radians = 6 Types of leveling survey are 1_ 2_ 3_ B) Draw graphical scale calinear scale of (1\5000) ?
FIND CENTROID (C.G.) FIND Ix WI2X40 WIZX40 Ix= 307 im" A- 11.7 in 307 int WT 6X20 A-5.84m エx14.イm 1.09 im. WIZX40 とWTGX20 21 の

Q6) Determine |AB| and coordinates of points C,D,E,F,G,H and X. N 79.08g S3 111.77159 s2 S1 144.3233g E A S4 293.03739 S5 252.1676g B (grad) a (grad) S (m) Y (m) x (m) STATION Ду Дх A 70.984 632.089 B 232.964 687.333 158.090 141.338 D 188.521 E 99.712 F 118.203 G 172.782 H 97.426 116.0859g 2806279g
1Q is 18 7T is 72
The calcula te Based and lengths shown, On The bearing and lantude departure, linear micclosure Of the traverre, If all station s have 0,953 angle and Pre cicion correction NCY? 104 35' G10, 45 10. o00 NCY) 10,000 ES 30¢'54' 6 47,02 sian'on Bea ing lLength 26°10' 04° 35' l ar 30' 358°18' 306°4! A 285.10 G10.45 720,48 203.00 E 69 7.02 195 30 358 18 203 .00
SITUATION 1- Hissing Data Given: Traverse with omitted measurements. (a) Calculate the distance of line GA (b) Determine the bearing of line CD TRAVERSE DATA W/ OHITTED MEASUREMENTS UNE LENGTH (m) BEARING AB 550.00 S 80.00° W BC 295.00 N 40.00° W CD 610.00 DE 885.00 S 72.00° E EF 455.00 S 18.00° E FG 500.00 S 80.00° W GA N 30.00 W
If the 4 holes in the drawing below are produced at .410" in diameter, what is the total positional tolerance of the holes? O .040 O .020 O .035 D O .410 Ø3.000 .020 45° 4X Ø.395-.430 Ø.500-.510 0.020MABMCM +0.010M ADM -.375-.395 +.000MABM C Ø2.000 A 0.005MA B