Obtain the solution using Integrating Factors Found by Formulas 1. 2(2y² + 5xy – 2y + 4)dx +x(2x + 2y – 1)dy = 0 2. УСу + 2х — 2)dx — 2(х + у)dу %3D0 3. хуdx - (x? + 2y?)dy %3D 0 III.

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
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Obtain the solution using Integrating Factors Found by Formulas
1. 2(2y² + 5xy – 2y + 4)dx +x(2x + 2y – 1)dy = 0
2. УСу + 2х — 2)dx — 2(х + у)dу %3D0
3. хуdx - (x? + 2y?)dy %3D 0
III.
Transcribed Image Text:Obtain the solution using Integrating Factors Found by Formulas 1. 2(2y² + 5xy – 2y + 4)dx +x(2x + 2y – 1)dy = 0 2. УСу + 2х — 2)dx — 2(х + у)dу %3D0 3. хуdx - (x? + 2y?)dy %3D 0 III.
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