of the following are true EXCEPT: An empty tree is defined to have a height of The depth of a node p is the number of ances The height of a tree to be equal to the maxim The height of a node p in a tree T:
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A: I have given explanation of given question is given below.
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A: Answer:
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A: There is one tree given, Apply Min-Max and Alpha-Beta on the tree.
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Q: of a node are less than the info in all of the nodes in the right subtree of the node. True False
A: Answer is : True
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- A binary tree is balanced if every node in the tree is such that the heights of its left and right subtrees do not differ by more than one. Complete the pseudo-code method isBalanced which determines if a binary tree is balanced. The function returns a value of -1 if the tree is not balanced, otherwise it returns the height of the tree. Add comments to explain what your code segment is doing. The following definition of a node in the tree is used. class BinaryNode { int element; BinaryNode left; BinaryNode right; } Complete the method below: int isBalanced (BinaryNode t) { int leftCount=0; int rightCount=0; if (t == null) //empty tree, height is 0 return 0; if ((t.left== null) and (t.right== null) return 0; else { . . . . . . . . . } }a) Write a function that will print the even elements in each level of the binary search tree. b) Write a function that will count total number of odd nodes of the tree. 10 / \ 6 13 / \ / \ 3 8 11 16 The output of the given tree when the function is applied: 10 6 8 16 Total number of odd nodes is 3. You have to answer both (a) and (b) in same code calling from main function. The base code is given bellow. Modify and write only the main function and the additional function needed to solve the problem in the answer script. BST code: #include<iostream> using namespace std; struct node { int key; struct node *left, *right; }; // A utility function to search a given node bool search(struct node* root, int key) { // Base Cases: root is null or key is present at root if (root == NULL) return false; else if(root->key == key) return true; // Key is greater than root's key else if…Q5. a. A binary search tree may be balanced or unbalanced based on the arrangement of the nodes of the tree. With you knowledge in Binary search tree:i. Explain the best and worst case scenarios of the time and space complexity of both type of binary trees above.b. Using your knowledge in binary tree traversals, implement the following tree traversing algorithms in either Java or C++, i. inorder, ii. preorder iii. and postorder traversal
- Define the Functor class and explain the idea of a Functor. Give an example of a Functor for a binary tree with data stored in nodes and leaves as part of your answer: data Tree a = Leaf a | Node a (Tree a) (Tree a) Tree a = Leaf a | Node a (Tree a) Tree a = Leaf a | Node a (T (200 words max. without code).Write a C++ program to implement binary search tree (BST). Your program should accept a list ofnumbers from the user (minimum 5) and then build a binary search tree from those numbers.Implement following functions: Serach function: Number is found or not leavesCount: Returns number of leaves in binary tree inorder: Print the contents of tree using inorder traversal Note: Define three files: bst.h, bst.cpp, main.cpp to solve this problemIn DrRacket: Define the difference between Binary Search Trees and Nodes? A) A Binary Search Tree is a Node, but a Node isn’t always a Binary Search Tree. B) A Node is a Binary Search Tree, but a Binary Search Tree isn’t always a Node. C) Binary Search Trees may contain Nodes, but Nodes cannot contain Binary Search Trees. D) Nodes may contain Binary Search Trees, but Binary Search Trees cannot contain Nodes. E) They are the same thing
- Define a Haskell instance of the Functor class for the following type of binary tree with data in nodes and leaves:data Tree a = Leaf a | Node a (Tree a) (Tree a)Suppose we have a tree type and a variable t defined as follows: datatype tree = Node of tree * int * tree| Leafval t = Node(Node(Leaf, 1, Leaf), 2, Node(Leaf, 3, Leaf))Note that t is a tree of the following form:Node 2/ \Node 1 Node 3/ \ / \L L L L Write a function maxTree that finds the maximum values within a tree.For example, maxTree t returns 3. Note that this is NOT a searchtree. This function assumes that the input tree is not a Leaf. IN SML SHOW OUTPUT WORKINGWrite a program in C++ to do the following: a. Build a binary search tree, T1. b. Do a postorder traversal of T1 and, while doing the postorder traversal, insert the nodes into a second binary search tree T2. c. Do a preorder traversal of T2 and, while doing the preorder traversal, insert the node into a third binary search tree T3. d. Do an inorder traversal of T3. e. Output the heights and the number of leaves in each of the three binary search trees.
- In c++ A company wants to store his Employees data but orderly. Because of that owner wants to use a binary search tree. Each Node must store the employee number, name, and salary double (class). Implement in java/C++ a binary search tree that stores the employees and implements the following methods: a) Include a new Employee (insert values) b) Search an employee given its number. c) Delete an employee. d) Get in-order, pre-order, post-order traversal of tree and display values.Create a binary linked tree, and traverse the tree by using the recursive function. The structure of the tree is as follow: //PICTURE// You should input the nodes in pre-order sequence. If a child of a node is NULL, input a space. Write the function of create binary tree, pre-order to print the nodes, in-order to print the nodes and post-order to print the nodes. Count the height of the tree.C++ Consider the binary search tree in the figure below. The numbers simply label the nodes so that you can reference them; they do not indicate the contents of the nodes. The answer to this question is the node position to the left of the node (the numbers 1-31). Beginning with an empty binary search tree, consider the binary search tree that is formed when you insert the following values in the order given: B, T, E, A, N, W, J At what position is N?