One of the bartleby experts helped me with this homework problem. I am having trouble reading the handwriting from parts (a) to (c). Can you rewrite the work that was provided for this homework problem?   Statistically speaking, the typical romantic couple spends 3 hours of quality time together each day, with a variance of 1.5 hours. During my teenage years, I was under the assumption that a friend and I were a couple, but she recently pushed back on that claim. So, I logged our time spent together over a period of 92 days. As it turned out, we spent 2.65 hours together on a typical day, again with a variance of 1.5 hours. Assuming that all of the time we spend together is “quality” and that relationship time spent is governed by the normal distribution, do I have sufficient statistical evidence to claim that we were, in fact, in a romantic relationship? ˆ(a)  Find and interpret the z-score of our time spent together, specifically referencing what information the sign (positive/negative) of the z-score tells us. ˆ(b)  Conduct a hypothesis test to determine whether our 2.65 hours of quality time differs significantly from the socially-accepted 3-hour figure. ˆ (c) Create and interpret a 95% confidence interval about our mean time spent together. ˆ(d) In light of all of this information, provide a conclusion: are we, or aren’t we?

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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One of the bartleby experts helped me with this homework problem. I am having trouble reading the handwriting from parts (a) to (c). Can you rewrite the work that was provided for this homework problem?

 

Statistically speaking, the typical romantic couple spends 3 hours of quality
time together each day, with a variance of 1.5 hours. During my teenage
years, I was under the assumption that a friend and I were a couple, but she
recently pushed back on that claim. So, I logged our time spent together over a
period of 92 days. As it turned out, we spent 2.65 hours together on a typical
day, again with a variance of 1.5 hours. Assuming that all of the time we spend
together is “quality” and that relationship time spent is governed by the normal
distribution, do I have sufficient statistical evidence to claim that we were, in
fact, in a romantic relationship?


ˆ(a)  Find and interpret the z-score of our time spent together, specifically
referencing what information the sign (positive/negative) of the z-score
tells us.


ˆ(b)  Conduct a hypothesis test to determine whether our 2.65 hours of quality
time differs significantly from the socially-accepted 3-hour figure.
ˆ

(c) Create and interpret a 95% confidence interval about our mean time spent
together.


ˆ(d) In light of all of this information, provide a conclusion: are we, or aren’t
we?

 

 

 

2
(b) We
Ho:
fe
=
3 = 10
HI: μ = 2.65 < 3
2=
have
under Ho
√(x-1)
Let
to test
Then
L:
is
P= P(Z -2.7408]
= 0.00306
ワー
2,7408
Level of signific
be
0.05
Þ(= 0.00306) < d (= 0.05)
We Reject Hto
and conclude
/
that
2.65 hours of quality time
significantly from socially
accepted 3 hour figure
differs
cance
100 (1-0)% confidence interval (C#)
is
given as
Z Z
P[- 3042²
3042] =
1-2= 0.95, 2= 0,05, 2/2 = 0.095
3212= 30.025
= 1.96
Therefore,
3
P[-1.96 <√(-) <1-96] = 0.95
P[ 5-1.96.5 μ< = + 1.96 F ]
√n
P[ 2.65 0.25 μ< 2,65+ 0.25]
=P[ 2.4 < M < 2.9]
95% CI fort is
(2.4, २१).
I
1
I
T
I
I
1
1
1
1
T
1
1
I
1
T
Transcribed Image Text:2 (b) We Ho: fe = 3 = 10 HI: μ = 2.65 < 3 2= have under Ho √(x-1) Let to test Then L: is P= P(Z -2.7408] = 0.00306 ワー 2,7408 Level of signific be 0.05 Þ(= 0.00306) < d (= 0.05) We Reject Hto and conclude / that 2.65 hours of quality time significantly from socially accepted 3 hour figure differs cance 100 (1-0)% confidence interval (C#) is given as Z Z P[- 3042² 3042] = 1-2= 0.95, 2= 0,05, 2/2 = 0.095 3212= 30.025 = 1.96 Therefore, 3 P[-1.96 <√(-) <1-96] = 0.95 P[ 5-1.96.5 μ< = + 1.96 F ] √n P[ 2.65 0.25 μ< 2,65+ 0.25] =P[ 2.4 < M < 2.9] 95% CI fort is (2.4, २१). I 1 I T I I 1 1 1 1 T 1 1 I 1 T
(@)
Romantic
population
Variance
x
Then
(X)
A random sample of size n=92
L
has
been
x
X1
Z=
At
2=
Couple have
mean
fe= 3
ре
3=
2
Variance σ = 1.5
taken from normal
with mean 3
and
has normal distribution
N (3, 1.5)
~ N( 3₂ 1105 )
92
In 5. That is
A
1
父-3
1^5
X-3
√0.01630
·2= 2.65
2.65-3
This means
N(0,1)
92
0.1277
الله
it is
-217408
~ N(0₂1)
Ĉ
6
x-3
0₁/277
O
-2.7408
Standard normal
below to mean
O
Transcribed Image Text:(@) Romantic population Variance x Then (X) A random sample of size n=92 L has been x X1 Z= At 2= Couple have mean fe= 3 ре 3= 2 Variance σ = 1.5 taken from normal with mean 3 and has normal distribution N (3, 1.5) ~ N( 3₂ 1105 ) 92 In 5. That is A 1 父-3 1^5 X-3 √0.01630 ·2= 2.65 2.65-3 This means N(0,1) 92 0.1277 الله it is -217408 ~ N(0₂1) Ĉ 6 x-3 0₁/277 O -2.7408 Standard normal below to mean O
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