Only one of these calculations is correct to evaluate the definite integral J. 2 In(x) sinh(x) dx Using the Trapezoidal Rule with n=4 Select one: O (2/4) [ 2 In(1.5) sinh(1.5) + 2 In(2) sinh(2) + 2 In(2.5) sinh(2.5) + In(3) sinh(3) ] O (2/6) [ 4 In(1.5) sinh(1.5) - 2 In(2) sinh(2) - 4 In(2.5) sinh(2.5) - In(3) sinh(3) ] O None O (2/6) [ In[1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) - 4 In(4) sinh(4) + In(5) sinh(5) ] O (2/2) [ In[1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) + 4 In(4) sinh(4) - In(5) sinh(5) ] O (2/4) [ In[1) sinh(1) - 2 In(2) sinh(2) + In(3) sinh(3) ]

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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Only one of these calculations is correct to evaluate the definite integral
2 In(x) sinh(x) dx
Using the Trapezoidal Rule with n=4
Select one:
O (2/4) [ 2 In(1.5) sinh(1.5) + 2 In(2) sinh(2) + 2 In(2.5) sinh(2.5) + In(3) sinh(3) ]
O (2/6) [ 4 In(1.5) sinh(1.5) + 2 In(2) sinh(2) + 4 In(2.5) sinh(2.5) + In(3) sinh(3) ]
O None
O (2/6) [ In(1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) + 4In(4) sinh(4) + In(5) sinh(5) ]
O (2/2) [ In(1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) + 4 In(4) sinh(4) + In(5) sinh(5) ]
O (2/4) [ In(1) sinh(1) + 2 In(2) sinh(2) + In(3) sinh(3) ]
Transcribed Image Text:Only one of these calculations is correct to evaluate the definite integral 2 In(x) sinh(x) dx Using the Trapezoidal Rule with n=4 Select one: O (2/4) [ 2 In(1.5) sinh(1.5) + 2 In(2) sinh(2) + 2 In(2.5) sinh(2.5) + In(3) sinh(3) ] O (2/6) [ 4 In(1.5) sinh(1.5) + 2 In(2) sinh(2) + 4 In(2.5) sinh(2.5) + In(3) sinh(3) ] O None O (2/6) [ In(1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) + 4In(4) sinh(4) + In(5) sinh(5) ] O (2/2) [ In(1) sinh(1) + 4 In(2) sinh(2) + 2 In(3) sinh(3) + 4 In(4) sinh(4) + In(5) sinh(5) ] O (2/4) [ In(1) sinh(1) + 2 In(2) sinh(2) + In(3) sinh(3) ]
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