lim-X dx→ lim (-xe¯x- e¯×)lim (-be-b- eb+1)хеb →000.b → 00-b|(-∞·0-0+1)= lim (-be-b)+1→ lim: )+1b →00b →∞eb→ lim: )+1--1+1=0+1=1 Convergentb → 00None . , xe* dx- lim (-x e¯* )l;→ lim (-b e-b+1)Only one of these calculations is correct to evaluate the definite integral-xхеdxSelect one:lim-xхеdx→ lim (-x e¯* )l→ lim (-b e-b+1)b → 00b →∞|(-00·0+1)=0+1=1 Convergent-xхеdx > lim (-xе *—е→ lim (-b e-b – e-b+1)-xlimb → 00|(-0∞·0-0+1 )=0-0+1=1 Convergentlimdx→ lim (-xe*- e¯*);→ lim (-be-b- e-b+1)хе>0.|(-∞·0-0+1)= -∞-0+1 = -∞ divergent

Explanation of the answer is as follows

Only one of these calculations is correct to evaluate the definite integral xe-X dx Select one: lim xe-* dx→ lim (-x e¯* )l;- lim (-b e¬b+1) хе b →0 °0 b +00 |(-·0+1)=0+1=1 Convergent lim b → 00 dx lim (-x e-*- e¯* )l;→ lim (-b e¬b– e +1) хе‑ b +00 |(-0·0-0+1)=0-0+1=1 Convergent Sxe*dx→ lim (-xe*- e*)l;→ lim (-beb-eb+1) → lim (-be-b- e-b+1) lim b-00 °0 |(-·0-0+1)= -∞-0+1 = - ∞ divergent b-00