11 Only one of these calculations is correct to evaluate the limit lim xtanxX+0+Select one:lim xtanx take Inx+0+Inxlim tanx Inx = lim= 0x+0+ (1/tanx)+ lim xtanx = e° = 1x+0+Take exponentialX+0+lim xtanx = 0° = 0X+0+lim xtanx + take InX+0+(1/x)(sin²x)= lim(2 sinx cosx)= 0(-1)Inxlim tanx Inx = lim= lim= limX+0+ (cotx)Take exponential + lim xtanx = e0 = 1(-x)x+0+x+0+ (-csc2x)X+0+X+0+X+0+tanv

Name: 11 Only one of these calculations is correct to evaluate the limit lim
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Description: 11 Only one of these calculations is correct to evaluate the limit lim xtanxX+0+Select one:lim xtanx take Inx+0+Inxlim tanx Inx = lim= 0x+0+ (1/tanx)+ lim xtanx = e° = 1x+0+Take exponentialX+0+lim xtanx = 0° = 0X+0+lim xtanx + take InX+0+(1/x)(sin²x)

The correct solution of given equation

Math

Calculus

Only one of these calculations is correct to evaluate the limit lim xtanx Select one: lim xlanx → take Iin Inx lim tanx Inx = lim - (1/ tanx) Take exponential - lim xtanx = e° =1 lim xtanx = 0° = 0 lim xtanx → take In x-0+ (1/x) lim (sin²x) = lim (2 sinx cosx) (-1) Inx lim tanx Inx = lim = lim (cotx) - (-csc²x) (-x) Take exponential - lim xtanx = e° =1

Only one of these calculations is correct to evaluate the limit lim xtanx Select one: lim xlanx → take Iin Inx lim tanx Inx = lim - (1/ tanx) Take exponential - lim xtanx = e° =1 lim xtanx = 0° = 0 lim xtanx → take In x-0+ (1/x) lim (sin²x) = lim (2 sinx cosx) (-1) Inx lim tanx Inx = lim = lim (cotx) - (-csc²x) (-x) Take exponential - lim xtanx = e° =1

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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