oof. Assume that n is an odd integer. Then n 2k + 1 for some integer k. Then %3D 7n - 5 = 7(2k+1) - 5 = 14k + 7-5 = 14k + 2 = 2(7k + 1). Since 7k + 1 is an integer, 7n- 5 is even. q.e.d.

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.7: Problem Solving: Consecutive Integers
Problem 14OE
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oof. Assume that n is an odd integer. Then n 2k + 1 for some integer k. Then
%3D
7n - 5 = 7(2k+1) - 5
= 14k + 7-5
= 14k + 2
= 2(7k + 1).
Since 7k + 1 is an integer, 7n- 5 is even. q.e.d.
Transcribed Image Text:oof. Assume that n is an odd integer. Then n 2k + 1 for some integer k. Then %3D 7n - 5 = 7(2k+1) - 5 = 14k + 7-5 = 14k + 2 = 2(7k + 1). Since 7k + 1 is an integer, 7n- 5 is even. q.e.d.
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