| 2. tan @ + 2tan?@ + 1 4 n4 @ tan4

Q: 00 How were sin(x) = [° (−1)²₂2k+1₁ -X these values generated from k=0 (2k+1)! (1) (0) n=0 n!

A:

Q: Find the exact value of 2tan 15° /(1 - tan2 15°)..

A:

Q: 3ミ れニ」 ny.Sin?n 2パッ7

A:

Q: (a) Verify that tanh P-tanh Q 1-tanh P tanh ọ tanh( P – Q)

A:

Q: 2/ Fine the derivetiveofafunction さ tan! Xー!

A: From the given problem:   y=tan-1x-1x+1   As we know that:   dtan-1xdx=1x2+1

Q: if tan A = 4/7 and tan B =5/2 what is tan (A-B)

A: Here we have to find out the value of a-b

Q: 16. tan²(x) + sec²(x) = 1 O True O False

A: Consider a right angled triangle.

Q: tan (A + B) = 9 and tan B = 4/5  how can i find tan A ?

A:

Q: 1 Evaluate sin (7/6 + 2e de. 2ei de. 2n Jo

A:

Q: Let h(x) = tan(2x + 2). Then h'(2) is and h''(2) is

A: The given function is: h(x)=tan(2x+2)

Q: 4. Evaluate tan²(x)dr. | tan

A:

Q: Find sin(0) 13 12 O 5/13 O 12/13

A:

Q: الواجُب (x-1) (x+4)<o 2 )و - رصه - (

A:

Q: 5. Show that de (tan 8) can be expressed in the form 3tan 8+3sec2e-3. Hence, find tan*e de.

A:

Q: what is Selution of DE (D-20)Y=ê Sinx When Sotved using the meth ed of undetermind

A:

Q: 1 Evaluate sin'(76 + 2e de. 2n Jo

A:

Q: 4 tan 0 = 3 Find sin 20 where 27 < 0 < 2 25 24 7 24 24 25 25

A:

Q: EVALUATE ap- x2 + 64 O x – 8tan + c 8 O none O x – tan -1 +c 8 1 uis2 – a 8 x - -sin +

A:

Q: 15. Σ sin?k k3 k=1

A:

Q: Prove that : <(tan"e) - Ve +1 2e 2 +. Ve? +1 tan

A:

Q: Find θ with 0≤θ<2π  and tanθ=1

A: 0≤θ&lt;2π  and tanθ=1

Q: a) {tan"(n²)} p-1 n=1

A: There are multiple question. As per company policy kindly ask other question separately. a. This…

Q: 38) - con A) 0 sec B) 5π T, 13л 5т D) 0 3 12 12

A: Find the value of x which satisfy sec(x/2)=cos(x/2)

Q: claim you make. 00 1 tan n² n=1 (a)

A: Using the limit comparison test.

Q: What is ! 2 ? tanh -1 o 0.549 + 1.571i o 0.549 - 1.571i O -0.549 - 1.571i O -0.549 + 1.571i

A: Here we find value of arctanh(2) =?  We know that arctanh(z) = (1/2) [log(1+z/1-z)]

Q: Prove (05t - sin 4t tos?t

A:

Q: 29 21 20 What is tan A? 20 1 2 3 O O OO

A: tanA = (perpendicular/base) Perpendicular = BC = 21 Base = AB = 20

Q: -1 Prove sin xdx = --1 2

A: First we will find the solution for indefinite integral ∫sin-1x dx then we will find the solution of…

Q: Let h(x) = tan(3x + 7). Then n'(5) is and h'"(5) is

A:

Q: 41. tan? x – V3tan x=0

A: Part 41,Given,tan2 x - 3 tanx = 0

Q: 3. Evaluate 26 tan xdx

A:

Q: ( Σα - xi-1) = x = x for n > 2. i=2 11 IDDLE: following "proof" th

A: Given that c, x1, x2, ..., xn, y1, y2, ..., yn are 2n+1 given numbers.

Q: 4. Evaluate tan'x-sec xdx tan' x tan'x tan' x 5 tan' x tan'x tan' x tan'x tan' x A. C. 3 В. 7 +C 3…

A: use the formula  ................(1)

Q: Find the exact value of the expression. tan(8t/7) – tan(1/7) - 1 + tan(87/7) tan(n/7)

A: The expression is: tan8π7-tanπ71+tan8π7tanπ7 To find the exact value.

Q: pose m and n are const (-)+(+)x] + C m-n m+n [-cos(m-nx- -cos(m-n)x - cos(m + n)x] + C 1 m+n…

A:

Q: 2. tan 2 7 with 180° < I< 270° 3 given tan x

A: It is given that

Q: #4 anros y" +47= sin (2x) Hint: you need to modify one time. Long Алаевна

A:

Q: 2 cos(За? + 5) + [62? + 2] (а) lim За2 + 5 0)2

A:

Q: 5- When the (4tan e. tanz e = 1),the value of (6) from 0° to 360°.

A:

Q: x P(x) 0 0.03 1 0.34 2 0.27 3 ??

A: Let , the probability distribution of X is given. Our aim is to find the missing probability i.e.…

Q: π/4 1 If /n= 0, tan"x dx then 130 + 128 Answer:

A:

Q: evaluate sin(4 – 3i) O 9.71Z137.592° O 9.71/42.408° 9.71Z- 137.592° 0 9.714 42.408°

A: The given problem is to evaluate and simplify the given complex expression and express in polar…

Q: h₂ = = 3.75 sin(736t) + 7.5 and h₂ = 3.75 sin(736(t + 4))+ +7.5

A: answer of given question is in next step

Q: Is tan 3pi/2 undefined

A:

Q: Let sin A = 3/5 with A   tan  2 A

A: Given: sinA=35 To find: tan2A Solution: We know that, sinA=perpendicular(p)hypoetnuse(h) On…