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| (6x – 3* dx = / (бх f(u) du where u = (enter a function of x) dx (enter a function of x) = np a = |(enter a number) b = (enter a number) f(u) = (enter a function of u). The value of the original integral is

| (6x – 3* dx = / (бх f(u) du where u = (enter a function of x) dx (enter a function of x) = np a = |(enter a number) b = (enter a number) f(u) = (enter a function of u). The value of the original integral is

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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HWE3P15. 

 

PLEASE USE THE METHOD OF U SUBSTITUTION

|(6x – 3)* dx = /" (бх f(u) du - where u = (enter a function of x) du = dx (enter a function of x) a = |(enter a number) b = (enter a number) f(u) = (enter a function of u). The value of the original integral is
Transcribed Image Text:|(6x – 3)* dx = /" (бх f(u) du - where u = (enter a function of x) du = dx (enter a function of x) a = |(enter a number) b = (enter a number) f(u) = (enter a function of u). The value of the original integral is
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