|--E Q3) In a long-shunt compund generator, the terminal voltage is 230 V, when it delivers 150 A. The shunt field series field, divider, and armature resistances are 92, 0.015, 0.03, and 0.032 ohm respectively. Determine : (i) induced emf? (ii) total power generated armature?
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- Two synchronous machines are connected as shown in Figure 1. All values in the diagram are in per unit on a common system base. If the inputs and outputs to the two machines are represented by ?1? , ?1? , ?2? ,and ?2? respectively, derive expressions for input and output power for the equivalent machine. If ?1 = 4.5 ??/??? and ?2 = 6.0 ??/???, calculate the inertia constant, input power, and the maximum power of the equivalent machine. Assume ?1? = 1.25 ?? , ?2? = 1.1 ??. Write the swing equation of the equivalent machine.A shunt generator supplies a 31kW load at 230V through cables of resistance, R = 122mΩ. If the field winding resistance, Rf =50Ω and the armature resistance, Ra =51mΩ. Determine the following below: The terminal voltage is, Answer and unit for part 1 The e.m.f. generated in the armature is,A long shunt cumulative compound dc generator delivers a load current of 60A at 440V. The shunt field resistance , series field resistance and armature resistance are 80, 0.9 and 0.4 respectively. Calculate the induced emf and load resistance.
- (a) A short shunt cumulative compound dc generator supplies 6kW at 235V. The Shunt field resistance, Series field resistance and Armature resistances are 8012, 0.192 and 0.22 respectively. Calculate the induced emf and load resistance.A shunt generator supplies a 30kW load at 215V through cables of resistance, R = 110mn. If the field winding resistance, Rf =680 and the armature resistance, Ra =45mn. Determine the following below: The terminal voltage is, The e.m.f. generated in the armature is,A separately excited generator has no-load voltage of 125V. A certain load rated at 1200W, 120V is then connected at the terminal. Calculate the series resistance needed to connect to the armature circuit in order for the load to operate at rated condition if the armature resistance is 0.0692Ω.
- The armature, series field and shunt field resistances of 125 kW, 250 V long shunt cummulative compound DC generator are 0.025 ohms, 0.01 ohms and 30 ohms respectively. If stray power loss at rated load is 5 kW, determine the power in the armature field4. A 6 pole wave wound shunt generator delivers 200A at a terminal voltage of 240V. Ra and Rsh are 0.03Ω and 70Ω respectively. Neglecting brush drop, determine (i) armature current (ii) current per parallel path (iii) generated voltage and (iv) Power developed. armature current ? current per parallel path ? generated voltage ? Power developed ?In a long-shunt compound generator, the terminal voltage is 220 Vwhen generator delivers 110 A. Determine (a) induced emf and (b)total power generated. Given that shunt field, series field,diverter and armature resistances are 90 Ω, 0.025 Ω, 0.04 Ω and0.03 Ω respectively.
- A short shunt compound DC generator delivers a load current of 30 A at 220 V and has armature, series field and shunt field resistances of 0.05, 0.3 and 200Ω respectively. Calculate the induced emf, the armature current and the voltage regulation. Allow 1 V per brush for contact droWhat are FACTS (Flexible AC Transmission Systems) devices, and how do they enhance power system stability and control?the armature series field and shunt field resistance of a 125 kw, 250V long shunt cumulative compound DC generator are 0.025ohms, 0.01ohms and 30 ohms, respectively. If the stray power stray loss at rated load is 25 kW, determine the power in the shunt field. Assume a astray load loss of 1% of the load power output (note: Input power generator is equal to the motor brake horsepower, Pin=Pl+Plosses) Choices A. 2034.5 W B.2082.5 W C. 2065.5 W D. 2053.5 W