| The electrical network shown can be viewed as con- sisting of three loops. Applying Kirchoff's law (Evoltage drops = Evoltage sources) to each loop yields the following equations for the loop cur- rents i1, i2, iz: 20 Ω 5Ω mn-220 V ww i, iz -OV www 102 5i1 + 15(i1 – i3) = 220 V R(i2 – i3) + 5i2 + 10i2 = 0 20i3 + R(i3 – i2) + 15(i3 – i1) = 0 %3D Compute the three loop currents in terms of R. 152 wwww www

| The electrical network shown can be viewed as con- sisting of three loops. Applying Kirchoff's law (Evoltage drops = Evoltage sources) to each loop yields the following equations for the loop cur- rents i1, i2, iz: 20 Ω 5Ω mn-220 V ww i, iz -OV www 102 5i1 + 15(i1 – i3) = 220 V R(i2 – i3) + 5i2 + 10i2 = 0 20i3 + R(i3 – i2) + 15(i3 – i1) = 0 %3D Compute the three loop currents in terms of R. 152 wwww www

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Hi, I have been given this circuit but I am a bit doubtful about my problem solving steps. First of all, I have been given the magnitude and direction of i1 and i2, but not for i3 so I have guessed the direction since the current i1 and i2 meet to node B. As for the voltage source Vs, I have guessed the polarity because of the direction of i1, but I'm not sure if it is actually correct. In the last question (f) I have been asked to find the current i3, but I thought it was easier to calculate before point (e) in order to find the voltages Vs and Vb. I have then used KVL applied to the loops ADBA and loop BDCB. Could you let tell me if what I have done is correct of is there any mistake?
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