or the making of 6000 ft^3 of acetylene (CHCH) gas at 70 degrees F and 750 mm Hg, solid calcium carbide (CaC2) which contains 97 wt % CaC2 and 3 wt % solid inerts is used along with water. The reaction is CaC2 +2H2O --> CHCH + Ca(OH)2 The final lime slurry contains water, solid inerts, and Ca(OH)2 lime. In this slurry the total wt % solids of inerts plus Ca(OH)2 is 20%. How many lb of water must be added and how many lb of final lime slurry is produced? [Hint: Use a basis of 6000 ft3 and convert to lb mol. This gives 15.30 lb mol C2H2, 15.30 lb mol Ca(OH)2, and 15.30 lb mol CaC2 added. Convert lb mol CaC2 feed to lb and calculate lb inerts added. The total lb solids in the slurry is then the sum of the Ca(OH)2 plus inerts. In calculating the water added, remember that some is consumed in the reaction.]
For the making of 6000 ft^3 of acetylene (CHCH) gas at 70 degrees F and 750 mm Hg, solid calcium carbide (CaC2) which contains 97 wt % CaC2 and 3 wt % solid inerts is used along with water.
The reaction is CaC2 +2H2O --> CHCH + Ca(OH)2
The final lime slurry contains water, solid inerts, and Ca(OH)2 lime. In this slurry the total wt % solids of inerts plus Ca(OH)2 is 20%. How many lb of water must be added and how many lb of final lime slurry is produced?
[Hint: Use a basis of 6000 ft3 and convert to lb mol. This gives 15.30 lb mol C2H2, 15.30 lb mol Ca(OH)2, and 15.30 lb mol CaC2 added. Convert lb mol CaC2 feed to lb and calculate lb inerts added. The total lb solids in the slurry is then the sum of the Ca(OH)2 plus inerts. In calculating the water added, remember that some is consumed in the reaction.]
I know the final answer is 5200 lb water added and 5815 lb lime slurry but can anyone show me the work of how to get that??
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