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- Estimate the osmotic pressure of a solution of 0.1 M NaCl at 25°C. Assume 100% ionization of solute.Assume that a beaker is divided in half by a membrane which is permeable to water only. A 0.45 M glucose solution is on one side of the membrane, and a 0.40 M NaCl solution is on the other side of the membrane. (a) Diagram the above set-up, (b) indicate with an arrow the direction of water movement across the membrane and (c) explain, specifically, why the movement occurs in that directionThe CMC of SDS is 8.2 mM at 25 °C. Please describe the biological membrane solubilization when [SDS] is below or above 8.2 mM in the solution.
- In a photosynthetic investigation, a student measured the following pH of the stroma and the inner thylakoid compartments of spinach leaf cells at the conclusion of the experiment. Source of Fluid pH (mean) Standard Error of Mean (SEM) Stroma 8.2 0.75 Inner compartment of thylakoid 5.6 0.35 b. Construct an appropriately labeled graph to illustrate the sample means of the two locations to within 95% confidence (i.e. sample mean + 2 SEM).You are considering transport of Fe3+ out of a biological cell with a membrane potential of -60 mV. What is the value for delta psi in this case? (Make sure you express this value in proper units, i.e., as you would enter this value into the change in free energy of transport equation.)The average time it takes for a molecule to diffuse adistance of x cm is given byt = x2/2D where t is the time in seconds and D is the diffusioncoefficient. Given that the diffusion coefficient ofglucose is 5.7 × 10−7cm2/s, calculate the time it wouldtake for a glucose molecule to diffuse 10 μm, which isroughly the size of a cell.
- Calculate for the water activity of the soy sauce in 80.3% ERH. Suppose the soy sauce is subjected to a storage area with RH of 95.9%. What will be the water activity of the soy sauce?Indicate the hinge region, GK kinaseselectivity pocket and explain "Solvent AccessibilitySurface" and indicate the salt forming group at ATPbinding siteIf I slid a plant cells with a water potential averaging -.5 MPa Are placed into solution with a water potential of -.3 MPa, which of the following would be the most likely outcome?
- Electrochemical gradients (a) power simple diffusion (b) are established by pinocytosis (c) are necessary for transport by aquaporins (d) are established by concentration gradients (e) are a result of both an electric charge difference and a concentration difference between the two sides of the membraneYou are attempting to rupture cells. You systematically dilute a lysis buffer of ammonium sulfate in water and find that 54 mM is the point at which the cells rupture. You know that the internal osmolarity of the cells is 0.3 osM. Calculate the yield stress of the cell wall/membrane.A daisy stem is placed in a solution with a water potential of -0.2 bars. After the daisy stem cells have had a chance to reach equilibrium with the surrounding solution, the pressure potential inside the daisy cells is 0.5 bars. At equilibrium, calculate the solute potential of the daisy cells.