other leg th than twice the sho product rule be applied directly? Explain. + 11) sides of the triang (x - 3)(2x + 1) = 0 or (x - 3)(2x +1) = 6 211x- 98. If the square of a Dx+19x- For Exercises 78-93, solve the equation using the zero product rule. the result is -4. F 99. The product of tv + 4v) 78. (4х — 1)(3х + 2) %3D 0 more than 14 tim 4V 79. (а — 9)(2а - 1) 3 0 100. The base of a tria the height. If the find the base and 80. 3w(w +3)(5w +2) = 0 62 81. 6u(u - 7)(4u - 9) = 0 2(5c)(8d) + 82. 7k2-9k - 10 = 0 Ocd +64d

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter9: Solving Quadratic Functions
Section9.5: Solving Quadratci Equations Using The Quadratic Formula
Problem 56E
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I am stuck on 82

other leg
th
than twice the sho
product rule be applied directly? Explain.
+ 11)
sides of the triang
(x - 3)(2x + 1) = 0 or (x - 3)(2x +1) = 6
211x-
98. If the square of a
Dx+19x-
For Exercises 78-93, solve the equation using the zero
product rule.
the result is -4. F
99. The product of tv
+ 4v)
78. (4х — 1)(3х + 2) %3D 0
more than 14 tim
4V
79. (а — 9)(2а - 1) 3 0
100. The base of a tria
the height. If the
find the base and
80. 3w(w +3)(5w +2) = 0
62
81. 6u(u - 7)(4u - 9) = 0
2(5c)(8d) +
82. 7k2-9k - 10 = 0
Ocd +64d
Transcribed Image Text:other leg th than twice the sho product rule be applied directly? Explain. + 11) sides of the triang (x - 3)(2x + 1) = 0 or (x - 3)(2x +1) = 6 211x- 98. If the square of a Dx+19x- For Exercises 78-93, solve the equation using the zero product rule. the result is -4. F 99. The product of tv + 4v) 78. (4х — 1)(3х + 2) %3D 0 more than 14 tim 4V 79. (а — 9)(2а - 1) 3 0 100. The base of a tria the height. If the find the base and 80. 3w(w +3)(5w +2) = 0 62 81. 6u(u - 7)(4u - 9) = 0 2(5c)(8d) + 82. 7k2-9k - 10 = 0 Ocd +64d
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