Answer P02 given P01 P02:Determine the modular ratio 'n' and the modulus of rapture 'fr' for each case in P01 foreach case shown in P01.f₁=7.5A√f'psin=29000 (ksi)E. (ksi)11-f₁=0.624/f' N/mm²200000 (MPa)E, (MPa) P01: Calculate the modulus of elasticity Ec for each case shown in table:E₁=33w²5 √√, psiDensity180 pcf160 pcf145 pcfE,=0.043w¹ √√ MPa2550 kg/m³2400 kg/m³2300 kg/m³f'c5000 psi4000 psi3000 psi45 MPa40 MPa25 MPa

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P02: Determine the modular ratio 'n' and the modulus of rapture 'fr' for each case in P01 for each case shown in P01. f₁=7.54√f, psi n= 29000 (ksi) E. (ksi) 11- 1₁=0.624/f' N/mm² 200000 (MPa) E, (MPa)

P02: Determine the modular ratio 'n' and the modulus of rapture 'fr' for each case in P01 for each case shown in P01. f₁=7.54√f, psi n= 29000 (ksi) E. (ksi) 11- 1₁=0.624/f' N/mm² 200000 (MPa) E, (MPa)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Beams

In structural engineering, a beam is a component made of a variety of materials (including steel alloys, and wood) that can resist loads applied laterally to the beam axis. Members, elements, rafters, shafts, and purlins are all terms used to describe beams.

Question

Answer P02 given P01

P02:
Determine the modular ratio 'n' and the modulus of rapture 'fr' for each case in P01 for
each case shown in P01.
f₁=7.5A√f'psi
n=
29000 (ksi)
E. (ksi)
11-
f₁=0.624/f' N/mm²
200000 (MPa)
E, (MPa)

P01: Calculate the modulus of elasticity Ec for each case shown in table:
E₁=33w²5 √√, psi
Density
180 pcf
160 pcf
145 pcf
E,=0.043w¹ √√ MPa
2550 kg/m³
2400 kg/m³
2300 kg/m³
f'c
5000 psi
4000 psi
3000 psi
45 MPa
40 MPa
25 MPa

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Step 1: Determining modular Ratio 'n'.

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