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p(2) = (2 + 3)°(2 + 1)(z – 3)ª %3D 2 a) Degree: b) Right hand end behavior: As ? ,y→ c) Left hand end behavior: As x ? v, y→ ? v h is Select an an

p(2) = (2 + 3)°(2 + 1)(z – 3)ª %3D 2 a) Degree: b) Right hand end behavior: As ? ,y→ c) Left hand end behavior: As x ? v, y→ ? v h is Select an an

Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter1: Systems Of Linear Equations
Section1.3: Applications Of Systems Of Linear Equations
Problem 41E
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1 p(z) = (z + 3)°(z + 1)(z – 3)ª (x + 3)°(æ + 1)(æ – 3)° a) Degree: b) Right hand end behavior: As a ? v c) Left hand end behavior: As x ? v d) The degree of the polynomial shown in the graph is Select an answer v ? v e) The y-intercept is f) How many turning points does the polynomial have? g) State the zeros from lowest x-value to highest, and their multiplicity:. with multiplicity with multiplicity with multiplicity h) Select the graph by using the characteristics from above: 10 to 9 10 10+ 10 8 -6 -5 -2 -7 10
Transcribed Image Text:1 p(z) = (z + 3)°(z + 1)(z – 3)ª (x + 3)°(æ + 1)(æ – 3)° a) Degree: b) Right hand end behavior: As a ? v c) Left hand end behavior: As x ? v d) The degree of the polynomial shown in the graph is Select an answer v ? v e) The y-intercept is f) How many turning points does the polynomial have? g) State the zeros from lowest x-value to highest, and their multiplicity:. with multiplicity with multiplicity with multiplicity h) Select the graph by using the characteristics from above: 10 to 9 10 10+ 10 8 -6 -5 -2 -7 10
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