π/4 tan 0 If u= sec 0, then d0= sec 0

Q: 8. S 3+9 tan² 0 sec² 0 de 0+tan3 0 9. [3 cos 0 e sin 0 do

A: Explanation of the answer is as follows

Q: d. sin-1 f. arcsin(sin( 47n )) h. sin(arcos(-4/5))

A:

Q: F sin(0) and tan(0) = 25 find sec(0). 24 %3D - %3D

A:

Q: tan-1 (xy)=3x2+sin-1(y) find dy/dx  this is the correct question sorry.

A: To find: the derivative of the below equation.

Q: (a) Find S(tan x)dx (b) Evaluate i sin 3x cos 3x dx d (c) Find (2x sin 2x + cos 2x) and hence…

A: a) ∫tan2πx dxb) ∫π9π6sin3x cos3x dxc) ddx2xsin2x+cos2x and ∫0π4x cos2xdx

Q: f/² sin() cos() sin() dx (Consider initially the first 2 terms)

A: We have to find the integral.

Q: sec K + csc K sin K + cos K tan K + cot K

A: Given seck+cosecktank+cotk=sink+cosk

Q: a. sin(0) b. cos(0) c. sec(0) d. csc(0) cot(0) е.

A: Consider a right-angled triangle ABC and a,b,c are the sides of ∆ABC.

Q: (cos 0 -sin 0) d0 7. J sin 0 8. J (1 – tan 0)² de. 9. sec2 0 tan² 0 d0.

A: 7. Given integral, ∫cos θ-sin θsin θdθ

Q: (cos 0 -sin 0) d0 7. J sin 0

A:

Q: Verify the identity.

A: The trigonometric identity is given as, sect-1t·sect=1-costt Consider the term in LHS,…

Q: sin? 0 2) cos 0 = sec 0- cos e %3D

A:

Q: (b) (-8, 15) sin(0) = cos(0) = tan(0) = csc(e) = sec(e) =

A:

Q: a/3 Find the value of cos(3x) dx.

A:

Q: | sin"(2)dz a. b. /a sec"(2)dz

A: Explanation and solutions is given below....

Q: (sec 0 + csc 0)(cos 0 – sin 0)

A:

Q: 22. tan?0 sec+0 d0 26. /4 sec'0 tan e de

A:

Q: (sin 20+1)d0 4. S sin²0+0

A: Given: I=∫(sin2θ+1)dθsin2θ+θ

Q: wer -0.7 Find -7 sec (5x + 4) tan(5x +4) dx. Show the steps th -1.1 S-

A:

Q: 4 sin e = cos 0 = tan 6 = csc e sec e cot 0 = 3.

A: The values are:

Q: C. tan 0 = 3 sin 0 over [0, 2n) %3D

A:

Q: sin H = 0.41 %3D

A: Given sin H=0.41H=arcsin(0.41)H=sin-1(0.41)

Q: a. cot 0 sec 0 tan? 0 sec² 0 1-sin? x с. csc2 x-1 b.

A: (a)  Consider the given expression cotθ secθ Since, cotθ=cosθsinθ Then, cotθ secθ=cosθsinθ…

Q: 3. V6 (a) sin e = cos e = tan e= cot e = sec 0= csc e= (b) sin B =

A: Definition used -               In a right angle triangle -                            sinθ =…

Q: Cos A +1+ sin A 2 sec A 1+ sin A %3D cos A

A: To Prove: cosA1+sinA+1+sinAcosA=2secA

Q: е. cos(arcos(-.2)) g. sec(arcsin(3/5)) i. tan(arcos(x/r))

A: We have to find the value of above trigonometric expressioslns. Please see the explanation below..

Q: cos 0 = ems 3' 2 sin 0 = csce = %3D cos0 = sec0 =_ tan 0 =_ cot0 = %3D 1/3

A:

Q: Eualhat At 5é sin (t-s)ds

A: Use the method of substitution to simplify the definite integral.

Q: Find the quadrant containing u if the given conditions are true.

A: We know that, 1. In first quadrant all trigonometric functions have positive value. 2. In second…

Q: sin(0) d0. cos²(0) Evaluate

A:

Q: Cosx 3. 3 cos r - 5 d.r, Use z = tanr |

A:

Q: . sin 20 tan B dọ + (sec ß - 1) cos o dß = 0 2 sin o + c p = 2 sec B + c %3D O = 2 tan ß + c = 2 cos…

A:

Q: dv 3. cot ( +9) 1-cos 2. COS

A: Given: ∫ecot-1v3dvv2+91-cos2ecot-1v3

Q: I sin r cos xdx. 6. Evaluate sin ¹3 3

A:

Q: Approximate to four decimal places, when appropriate.

A: Hey, since there are multiple sub-parts posted, we will answer first three sub-parts. If you want…

Q: 32. tan' 0 sec' 0 d0 3

A: To evaluate ∫tan3 θ sec3 θ dθ

Q: sin 30 4. sin e cos e 4 cos 0 – sec 0

A: To verify the identity: sin3θsinθ cosθ=4cosθ-secθ. Proof: We have an identity, sin3θ=3sinθ-4sin3θ…

Q: sec® tan Od® coso A) tane В sece sec?0

A: topic - indefinite integral

Q: cos a+1 tan² a cos a 1-sec a ||

A:

Q: sec 0 — сos cos O sin 0 sec 0 + cos 0 1 + cos? 0

A: To prove that,             secθ-cosθsecθ+cosθ=sin2θ1+cos2θ

Q: f sec 0 = -13/6 and sin 0 > 0, what is 3sine – cos(0)? 6+3/133 13 6–3/133 13 2+V133 13 2-V133 13 no…

A:

Q: f tan(0): and sin(0) < 0, then 3 %3D sin(e) = %3D cos(0) = %3D sec(0) = csc(0) = cot(0) =

A:

Q: cos –1 (-V)] 2 sec OS

A: Simplification

Q: Verify the identity.

A: Given,           The identity is cosθ+sinθtanθ=secθ .

Q: 32. tan?x sec x dx 7/2 35. cot'x dx

A: Topic :- Integration

Q: Cos O tan 0 66. lim 0→0

A: Consider the given function. limθ→0   cosθtanθθ

Q: 1+sin A cos 2 sec u – cos µ = sin µ tan µ 4. + 2 sec 1 %3D cos A 1+sin A

A: We have to verify the given identities.

Q: x = pi/18 [(tan(4x)+tan(x))/sin(x)]*cot(x) Simplest form?

A: The given expression is : tan4x+tanxsinxcosx  To write the given expression in the simplest form.