PA = - (13.6*1000*9.81*0.14) – (1000*9.81*0.2) + (1000*9.81*0.6) + (101.3*1000)+(0.83*1000*9.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft³ and 848 lbm/ft³, respectively. Oil Oil 32 in Mercury

PA = - (13.610009.810.14) – (10009.810.2) + (10009.810.6) + (101.31000)+(0.8310009.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft³ and 848 lbm/ft³, respectively. Oil Oil 32 in Mercury

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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