Part 1: Five thousand kilocalories (5000 kcal) of heat flows from a high temperature reservoir at 600 K to a low temperature reservoir at 300 K. What is the entropy change in the universe? Part 2: Now let us assume the same 5000 kcal of heat flows through a 20% efficient heat engine between the same reservoirs. a. Compute amount of heat converted into useful work. b. Compute the entropy change in the universe.

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Part 1:  Five thousand kilocalories (5000 kcal) of heat flows from a high temperature reservoir at 600 K to a low temperature reservoir at 300 K.

What is the entropy change in the universe?

Part 2:  Now let us assume the same 5000 kcal of heat flows through a 20% efficient heat engine between the same reservoirs.

a. Compute amount of heat converted into useful work.

b. Compute the entropy change in the universe.

Equations
(average speed) d= vot + }at² (distance under acceleration)
Fnet
W
= mg (Weight) a=
(Acceleration) F = Gmm2
(Gravity Law)
(Мотentum) КЕ%3D3mu?
(Kinetic Energy) PE =mgh (Potential Energy)
p= mv
W = F ·d (Work Done) Q= mcAT (Heat Energy) Q=mL (Latent Heat Energy)
eff = (Heat Engine Efficiency) eff = 1- (2nd Heat Engine Efficiency)
W
%3D
effCarnot = 1 – (Efficiency Carnot Cycle) S = $ (Entropy Change of Reservoir)
AS = H + c (Total Entropy Change Closed System)
Transcribed Image Text:Equations (average speed) d= vot + }at² (distance under acceleration) Fnet W = mg (Weight) a= (Acceleration) F = Gmm2 (Gravity Law) (Мотentum) КЕ%3D3mu? (Kinetic Energy) PE =mgh (Potential Energy) p= mv W = F ·d (Work Done) Q= mcAT (Heat Energy) Q=mL (Latent Heat Energy) eff = (Heat Engine Efficiency) eff = 1- (2nd Heat Engine Efficiency) W %3D effCarnot = 1 – (Efficiency Carnot Cycle) S = $ (Entropy Change of Reservoir) AS = H + c (Total Entropy Change Closed System)
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