Part 1: The base address is Ox10010000. What is the address of the memory location that holds Ox78? Pay attention that a word aligns in an address that is divisible by 4. Part 2: The base address is 0x10010000. What is the address of the memory location that holds 'a'? Please pay attention that each word gets 4 bytes. Therefore, to find the address of 'a' you need to add 4 bytes to the address of wordNum1. What value is saved in that location? Hint: ASCII code of 'a'.
Part 1: The base address is Ox10010000. What is the address of the memory location that holds Ox78? Pay attention that a word aligns in an address that is divisible by 4. Part 2: The base address is 0x10010000. What is the address of the memory location that holds 'a'? Please pay attention that each word gets 4 bytes. Therefore, to find the address of 'a' you need to add 4 bytes to the address of wordNum1. What value is saved in that location? Hint: ASCII code of 'a'.
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter2: Problem Solving Using C++using
Section2.3: Data Types
Problem 9E: (Practice) Although the total number of bytes varies from computer to computer, memory sizes of...
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Hello. Please answer the attached MIPS computer architecture question and all its two parts correctly.
*If you answer the question and all its two parts correctly, I will give you a thumbs up. Thanks.
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