Part 1. Suppose that you want to re-write an integral using a substitution, in this case, x11 1 dx = -- 6. 1- u du Vũ V1 – x6 Determine the correct substitution that will accomplish this. That is, find u as a function of x that allows you to re-write the integral as shown above. The function u(x) we want is in which case the differential of u is Note: answer should be in the form u = f(x) and du = f'(x)dx Part 2. Evaluate the indefinite integral above in terms of u. 1- u du = 1 Note: answer should be in terms of u only Part 3. Back substituting in the antiderivative you found in Part 2. above we have dx =| Note: answer should be in terms of x only

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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Part 1.
Suppose that you want to re-write an integral using a substitution, in this case,
x!1
dx =
V1 – x6
du
Vũ
6.
Determine the correct substitution that will accomplish this. That is, find u as a function of x that allows you to re-write the integral as shown above.
The function u(x) we want is
in which case the differential of u is
Note: answer should be in the form u = f(x) and du = f'(x)dx
%3D
Part 2.
Evaluate the indefinite integral above in terms of u.
-
du =
Vũ
Note: answer should be in terms of u only
Part 3.
Back substituting in the antiderivative you found in Part 2. above we have
x11
dx =|
VI- x6
Note: answer should be in terms of x only
Transcribed Image Text:Part 1. Suppose that you want to re-write an integral using a substitution, in this case, x!1 dx = V1 – x6 du Vũ 6. Determine the correct substitution that will accomplish this. That is, find u as a function of x that allows you to re-write the integral as shown above. The function u(x) we want is in which case the differential of u is Note: answer should be in the form u = f(x) and du = f'(x)dx %3D Part 2. Evaluate the indefinite integral above in terms of u. - du = Vũ Note: answer should be in terms of u only Part 3. Back substituting in the antiderivative you found in Part 2. above we have x11 dx =| VI- x6 Note: answer should be in terms of x only
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