Just need help with part 2 please! Jada has a way to find the probability of a random outcome being in event A or eventB. She says, "We use the probability of the outcome being in event A, then add theprobability of the outcome being in category B. Now some outcomes have beencounted twice, so we have to subtract the probability of the outcome being in bothevents so that those outcomes are only counted once."Jada's method can be rewritten as: P(A or B) = P(A) + P(B) - P(A and B)1. The table of data summarizes information about the 50 states in the United Statesfrom a census in the year 2000. A state is chosen at random from the list of 50. Letevent A be "the state name begins with A through M" and event B be "the populationof the state is less than 4 million."2. The table of data summarizes information about the 50 states in the United StatesPopulationPopulationPopulation< 4 Million24 MillionNames A thru M1115Names N thru Z1311Alaska is one of the 11 states in the top left cell of the table. California is one of the 15states in the top right cell of the table. Nebraska is one of the 13 states in the bottomleft cell of the table. New York is one of the 11 states in the bottom right cell of thetable. For each event, write which of the four states listed here is an outcome in thatevent.а. Aor Bb. Aс. Вd. A and BPart 2:Find each of the probabilities when a state is chosen at random:A. P(A or B)В. Р(А)C. P(B)D. P(A and B)

Part 2. P(A) = Probability that the state name begins with A through M =…

Answered: Part 2: Find each of the probabilities…

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Part 2: Find each of the probabilities when a state is chosen at random: A. P(A or B) В. Р(А) С. Р(В) D. P(A and B)

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section8.7: Probability

Problem 6ECP: In Pennsylvania’s Cash 5 game, a player chooses five different numbers from 1 to 43. If these five...

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Question

Just need help with part 2 please!

Jada has a way to find the probability of a random outcome being in event A or event
B. She says, "We use the probability of the outcome being in event A, then add the
probability of the outcome being in category B. Now some outcomes have been
counted twice, so we have to subtract the probability of the outcome being in both
events so that those outcomes are only counted once."
Jada's method can be rewritten as: P(A or B) = P(A) + P(B) - P(A and B)
1. The table of data summarizes information about the 50 states in the United States
from a census in the year 2000. A state is chosen at random from the list of 50. Let
event A be "the state name begins with A through M" and event B be "the population
of the state is less than 4 million."
2. The table of data summarizes information about the 50 states in the United States
Population
Population
Population
< 4 Million
24 Million
Names A thru M
11
15
Names N thru Z
13
11
Alaska is one of the 11 states in the top left cell of the table. California is one of the 15
states in the top right cell of the table. Nebraska is one of the 13 states in the bottom
left cell of the table. New York is one of the 11 states in the bottom right cell of the
table. For each event, write which of the four states listed here is an outcome in that
event.
а. Aor B
b. A
с. В
d. A and B
Part 2:
Find each of the probabilities when a state is chosen at random:
A. P(A or B)
В. Р(А)
C. P(B)
D. P(A and B)

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