Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. Year 1 data: 556 q² = frequency of bb (light) frequency of the dominant allele B is p = 1 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ 0.102 (2pq) +0.896_(q²) = 1] Genotypic frequencies are: Year 10 data: 56 q² = frequency of bb (light) 64 _light moths, 0.896 Genotypic frequencies are: dark moths ;q= 0.946 -9; p=1- 0.946 0.002 p² = frequency of BB (dark) 2pq = frequency of Aa (dark) 0.102 q² = frequency of aa(light). 0.896 638 _light moths,_ 0.080 0.282 frequency of the dominant allele B is p = 1 - q; p=1-0.282 _q= dark moths 0.054 0.718 Calculate genotypic makeup of the population. [0.718 (p) + 0.282 (9)1² = 1; 0.847 (p²) + 0.404 (2pq) +0.080 (q²) = 1] p² = frequency of BB (dark) 0.516 2pq = frequency of Aa (dark) 0.404 0.080 q² = frequency of aa(light)

Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. Year 1 data: 556 q² = frequency of bb (light) frequency of the dominant allele B is p = 1 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ 0.102 (2pq) +0.896_(q²) = 1] Genotypic frequencies are: Year 10 data: 56 q² = frequency of bb (light) 64 _light moths, 0.896 Genotypic frequencies are: dark moths ;q= 0.946 -9; p=1- 0.946 0.002 p² = frequency of BB (dark) 2pq = frequency of Aa (dark) 0.102 q² = frequency of aa(light). 0.896 638 _light moths,_ 0.080 0.282 frequency of the dominant allele B is p = 1 - q; p=1-0.282 _q= dark moths 0.054 0.718 Calculate genotypic makeup of the population. [0.718 (p) + 0.282 (9)1² = 1; 0.847 (p²) + 0.404 (2pq) +0.080 (q²) = 1] p² = frequency of BB (dark) 0.516 2pq = frequency of Aa (dark) 0.404 0.080 q² = frequency of aa(light)

Name: For the image attached did the moth population evolve? Explain. Is it
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Description: For the image attached did the moth population evolve? Explain. Is it micro or macroevolution? Part 4: Peppered Moth Allele and Gene FrequenciesThe dark allele in peppered moths is dominant (B= p). Light moths arehomozygous recessive (bb= q²). Use th

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter19: The Evolution Of Populations

Section: Chapter Questions

Problem 1VCQ: Figure 19.2 In plants, violet flower color (V) is dominant over white (v). If p = .8 and q = 0.2 in...

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