Part 4 (problem solving)Problem 1Calculate sag correction for a 30 m steel tape under a pull of 80 N, if it is suspended inthree equal spans. Unit weight of steel is 78.6 kN/m3. Area of cross-section of tape is 8mm2.Problem 2:A civil engineer used a 100m tape which is of standard length at 32°C in measuring a certaindistance and found out that the length of the tape has different lengths at different tensionswere applied as shown. K= 0.0000116 m/°c.Length of tapetension applied99.98610kg99.99414kg100.0320kga. What tension must be applied to the tape at 32°C so that it would be of standardlength?b. What tension must be applied to the tape at a temp. of 40.6°C so it would be ofstandard length?

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Answered: Part 4 (problem solving) Problem 1…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A 50-m steel tape weighs 1.05 kg and is supported at its endpoints and the 10-m and 25-m marks. If a pull of 6.0 kg is applied at the ends of the tape, what is the correction due to sag for a full tape length? a. 0.060 m b. 0.064 m c. 0. 050 m d. 0.500 m
An engineer used a 100m tape measuring an inclined distance. The measured length on the slope was recorded to be 659.2m long. The difference in elevation between the initial point and end point was found to be 3m. The 100m tape is of standard length at a temperature of 12℃.and a pull of 50N during the measurement the temperature reading is 25℃. And the tape was supported at both ends with an applied pull of 75N if A = 6.75mm^2, E= 200Gpa; mass of tape is 0.085kg/m, k= 0.0000116/℃.Find:a. Total correction per tape lengthb. The corrected slope or total lengthc. The horizontal distance
3.A civil engineer used a 30m tape in measuring an inclined distance. The measured length on the slope was recorded to be 459.20 m long. The difference in elevation between the initial point and the end point was found to be 1.25m. The 30m tape is of standard length at a temperature of 10°C and a pull of 50 N. During measurement the temperature reading was 15°C and the tape was supported at both ends with an applied pull of 75 N. The cross-sectional area of the tape is 6.50 sq. mm and the modulus of elasticity is 200GPa. The tape has a mass of 0.075 kg/m. a. determine the total correction per tape length. b. determine the correction for slope. c. determine the horizontal distance.
A line was recorded as 1750.00 meters long. The standard tape weighs0.65 kg , 30.00m long at 20°C under a 50N pull. During the actualobservation the temperature was 5°C and the tape was suspended undera 75N pull. It was also found that the tape is 3.00mm too long. If the linewas inclined at 3%. E = 200GPa, A = 2.50mm² and the coefficient of linearexpansion is 0.0000116 m/°C.(a) What is the actual inclined distance?(b) What is the actual horizontal distance.
A Civil Engineer used a 50m tape in measuring an inclined distance. The measured length on the slope was recorded to be 459.20 m long. The difference in elevation between the initial point and the end point was found to be 1.25 m. The 50 m tape is of standard length at a temperature of 10°C and a pull of 50 N. During measurement the temperature reading was 8°C and the tape was supported at both ends with an applied pull of 70 N. The cross-sectional area of the tape is 6 mm2 and the modulus of elasticity is 200 GPa. The tape has a mass of 0.075 kg/m. Coefficient of thermal expansion is 0.0000116 /°C. Determine the magnitude of the correction per tape length in meters due to temperature. Round off your answers to 4 decimal places. Determine the magnitude of the correction per tape length in meters due to pull. Round off your answers to 4 decimal places. Determine the magnitude of the correction per tape length in meters due to sag. Round off your answers to 4 decimal places. What is…
A Civil Engineer used a 50m tape in measuring an inclined distance. The measured length on the slope was recorded to be 459.20 m long. The difference in elevation between the initial point and the end point was found to be 1.25 m. The 50 m tape is of standard length at a temperature of 10°C and a pull of 50 N. During measurement the temperature reading was 8°C and the tape was supported at both ends with an applied pull of 70 N. The cross-sectional area of the tape is 6 mm2 and the modulus of elasticity is 200 GPa. The tape has a mass of 0.075 kg/m. Coefficient of thermal expansion is 0.0000116 /°C.Determine the magnitude of the correction per tape length in meters due to temperature. Round off your answers to 4 decimal places. Determine the magnitude of the correction per tape length in meters due to pull. Round off your answers to 4 decimal places. Determine the magnitude of the correction per tape length in meters due to sag. Round off your answers to 4 decimal places. What is the…
A Civil Engineer used 50 m. tape in measuring an inclined distance. The measured length on the slope was recorded to be 528.368 m. long. The difference in elevation between the initial point and the end point was found to be 6.369 m. The 50 m tape is of standard length at a temperature of 280C and a pull of 8 kg. During the measurement, the temperature reading was 350C and tape was supported for a full length with an applied pull of 12 kg. Cross sectional area of tape is 0.03 sq. cm., weight of tape is 0.50 kg. Determine the true horizontal distance.
A Civil Engineer used a 50m tape in measuring an inclined distance. The measured length on the slope was recorded to be 528.368 m. long. The difference in elevation between the initial point and the end point was found to be 6.369 m. The 50m tape is of standard length at a temp. of 28degC and a pull of 8kg. During the measurement, the temperature reading was 35degC and tape was supported for a full-length with an applied pull of 12kg. Cross sectional area of tape is 0.03 sq. cm., weight of tape is 0.50kg. Determine the true horizontal distance and the elastic modulus. COMPLETE SOLUTION PLEASE
Figure No. 5 Given q = 100 N/m, P = 60 N and Mo = 1000 N.m. L1 = 5m, L2 = 2m, and L3 = 2m
What must be the pull in a (7)(10) meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10% m? E = 2x101 N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends. Fundamentals of surveying
What must be the pull in a 70 meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10^-6m? E = 2x10^11N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends.
A 50m tape weighing 0.03kg/m is used to measure distance AB. The tape is supported at both end points and at its midspan and then applied tension is 6kg. Determine the total sag correction if the measured distance is 1,320.50m.

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Part 4 (problem solving) Problem 1 Calculate sag correction for a 30 m steel tape under a pull of 80 N, if it is suspended in three equal spans. Unit weight of steel is 78.6 kN/m3. Area of cross-section of tape is 8 mm2.