Part (a) Suppose you are implementing a method and the class it is in has a representation invariant. Does th impact your work? Answer YES or NO. If yes, explain how, and if no, explain why not Part (b) Complete the following hypothesis test so that it checks one aspect of list.append. @given(lists(integers()), integers()) def test_append(1st: List, v: int): ""Test that # TODO: Complete the docstring description and implement this function.
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- Write a method replace to be included in the class KWLinkedList (for doubly linked list) that accepts two parameters, searchItem and repItem of type E. The method searches for searchItem in the doubly linked list, if found then replace it with repItem and return true. If the searchItem is not found in the doubly linked list, then insert repItem at the end of the linked list and return false. Assume that the list is not empty. You can use ListIterator and its methods to search the searchItem in the list and replace it with repItem if found. Do not call any method of class KWLinkedList to add a new node at the end of the list. Method Heading: public boolean replace(E searchItem, E repItem) Example: searchItem: 15 repItem: 17 List (before method call): 9 10 15 20 4 5 6 List (after method call) : 9 10 17 20 4 5 6in java Write a method for the Linked Based List class which returns the largest item in the list. If the list is empty return null. Assume that class T is Comparable.DO NOT USE ANY OTHER METHODS OF THE LINKED BASED LIST CLASS. What is the worst case and best case complexity of the code in the previous problem? Explain your answer.Add a void instance method replaceAll(E oldE, E newE) in the MyLinkedList class to replace the occurrence of all oldE value with the specified newE value. Implement this method in O(n) time. import java.util.*; public class PExamCh24 { public static void main(String[] args) { new PExamCh24();}public PExamCh24() { // Create a list for strings MyLinkedList<String> list = new MyLinkedList<>(); // Add elements to the list list.add("America"); // Add America to the list System.out.println("(1) " + list); list.add(0, "Japan"); // Add Canada to the beginning of the list System.out.println("(2) " + list); list.add("Russia"); // Add Russia to the end of the list System.out.println("(3) " + list); list.addLast("Japan"); // Add France to the end of the list System.out.println("(4) " + list); list.add(2, "Japan"); // Add Germany to the list at index 2 System.out.println("(5) " + list); list.add(5, "Norway"); // Add Norway to the list…
- Please explain Q# 1, A list operation that produces one summary item result is called Group of answer choices A. Map B. Fold C. Filter D. Iterate Q#2, What is an accumulator? Group of answer choices A. An optional argument to a helper method B. An argument to a recursive method tracks information over the course of the recursion C. None of the above D. A recursive method that returns an accumulated valueTrying this again since part of my question keeps disappearing Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts public class ItemNode { private String item; private ItemNode nextNodeRef; // Reference to the next node public ItemNode() { item = ""; nextNodeRef = null; } // Constructor public ItemNode(String itemInit) { this.item = itemInit; this.nextNodeRef = null; } // Constructor…Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list def show_ids(M, level=0): k = M.first_node while k is not None: print(" "*2*level, id(k)) if (str(k.value.__class__.__name__) == str(M.__class__.__name__)): show_ids(k.value, level+1) k = k.next W=L2(Node(10, Node(L2(Node(14, Node(15, Node(L2(Node(16, Node(17))))))), Node(20, Node(30)))) )show_ids(W) Develop your solution as follows: - First copy the nodes of the current list (self) - Create a new list with the copied nodes - Loop through the nodes of the new list checking the value field - If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L):…
- Implement a simple linked list in Python (Write source code and show output) with basic linked list operations like: (a) create a sequence of nodes and construct a linear linked list. (b) insert a new node in the linked list. (b) delete a particular node in the linked list. (c) modify the linear linked list into a circular linked list. Use this template: class Node:def __init__(self, val=None):self.val = valself.next = Noneclass LinkedList:"""TODO: Remove the "pass" statements and implement each methodAdd any methods if necessaryDON'T use a builtin list to keep all your nodes."""def __init__(self):self.head = None # The head of your list, don't change its name. It shouldbe "None" when the list is empty.def append(self, num): # append num to the tail of the listpassdef insert(self, index, num): # insert num into the given indexpassdef delete(self, index): # remove the node at the given index and return the deleted value as an integerpassdef circularize(self): # Make your list circular.…java program : Given the following method to be considered within the SingleLinkedList class, what does this method do? public void Undefined() { Node<E> ptr = head; if (ptr == null || ptr.next == null) return false; E item1 = ptr.data; while (ptr.next != null) ptr = ptr.next; E item2 = ptr.data; if (item1.equals(item2)) { head = head.next; size--; } } If the first element of the list is equal to the second element of the list, then the method deletes the second node. If the first element of the list is equal to the last element of the list, then the method deletes the first node. If the first element of the list is equal to the second element of the list, then the method deletes the first node. If the first element of the list is equal to the last element of the list, then the method deletes the last node.Given the following definition of a single linked list, write a method that calculates and returns the sum of even integers in a linked list. public class SLL<E> { private static class Node<E>{ private E data; private Node<E> next; private Node(E dataItem) { data = dataItem; next = null; } private Node(E dataItem, Node<E> nodeRef) { data = dataItem; next = nodeRef; } } private Node<E> head = null; private int size = 0; }
- Build doubly-linked lists using a nested class called DoubleNode, where each node includes a reference to the item before it and the item after it in the list (null if there is no such item). Then put in place static methods for inserting at the start, inserting at the end, removing from the start, removing from the finish, inserting before a given node, inserting after a given node, and removing a given node.Write a code in python. Write down only the methods that are required; testers are not required. Complete the method below that takes the reference of a non-dummy headed singly linear linked list and removes all the nodes containing multiples of 5 from the list. remove_multiple_of_five(head)Give an example of a situation where you would use a tuple, set, or dict in place of a list. Just pick one, you don't have to explain all three, but do be specific about why the collection you picked would be more suitable for the situation that you describe than a list.