Part B: Create letter combinations of that consist of elements of list1 and list2. For example: A, A; A, C; A, D., H; J, A • You will need to separate the letter combinations and add them to lists: o Letter combinations will be appended to the list letter_combinations o Ifa letter combination already exists in letter_combinations, then it must be saved to the list repeated_combinations • You will need to output the combinations and repeated combinations

Part B: Create letter combinations of that consist of elements of list1 and list2. For example: A, A; A, C; A, D., H; J, A • You will need to separate the letter combinations and add them to lists: o Letter combinations will be appended to the list letter_combinations o Ifa letter combination already exists in letter_combinations, then it must be saved to the list repeated_combinations • You will need to output the combinations and repeated combinations

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 18PE

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Make a dictionary, the student's name is the key (a string) and the student's test scores is the value (a list). So it should be a dictionary with six key value pairs in it. Here is data to use. Brian,94,89,92 Rachel,100,90,65 Jon,67.5,95,100 Brit,0,78,80 Greg,65,100,78 Andrea,55.5,67,79 1. Now print the dictionary data using a loop that starts with for key, value in. 2. Now print the dictionary data using a loop that starts with for key in 3. Find and print out Rachels second score (should be a 90) 4. This one is a little tricky, a little mind-bender. Make a new dictionary. Using the dictionary you made from above,. the new dictionary should consist of the key is the name of the person, and the value is just the average of their scores. So it’s six key value pairs but instead of the value being a list like the first problems, this time it's just their average (which you compute from their scores in the other dictionary. Print the new dictionary out. 5. You…
????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…
????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…
Write a statement that creates a two-dimensional list with 5 rows and 3 columns. Then writenested loops that get an integer value from the user for each element in the list.
Replace XXX in the following function header for a doubly-linked list: ListInsertAfter(listName, currentNode, XXX) Group of answer choices headNode tailNode middleNode newNode
Considering all the elements and its indexes at the right side:Write a sequence of List operations that would result to a LIST that contains ONLY the elements with its respective indexes: {index[00]=104, index[01]=165, index[02]=115, index[03]=384, index[04]=248, index[05]=117}.
I have given you the linear search code example on the video and I want you to go through the code and adjust the code. In the following code, list consists of number 4 twice however when you execute this code you find only the first 4. Please adjust your code to find both 4’s on the list def linear_search(list1,key): for i in range(len(list1)): if key==list1[i]: print("Element is found at index", i) break else: print("The element is not found") list1=[4,5,10,4,9,21] key=int(input("Enter a key number: ")) linear_search(list1,key)
Complete the below function which takes a list of distinct positive integers and a target positive integer value, and then returns a list of the pairs of integers where each pair sums up to the target value. Each pair is represented as a tuple. For example, pairsum([3,2,6,1,5,4], 7) should return[(1,6), (2,5), (3,4)]If there are no pairs matching the target value, then you should return an empty list. IMPORTANT: the first integer in a tuple must be always smaller than the second integer. So, (5,3) is wrong and (3,5) is correct, and the resulting list must be in ascending order of first element in each tuple.
What is the functionality of the following piece of code? public int function(){Node temp = tail.getPrev();tail.setPrev(temp.getPrev());temp.getPrev().setNext(tail);size--;return temp.getItem();}a) Return the element at the tail of the list but do not remove itb) Return the element at the tail of the list and remove it from the listc) Return the last but one element from the list but do not remove itd) Return the last but one element at the tail of the list and remove it from the list
Three strings are read from input and stored into list musicians. Then, three more strings are read from input and stored into list years_played. Lastly, string separator_char is read from input. Output the following lines: "Musicians", with a field width of 17, centered. Then "Years Played", with a field width of 17, centered. 34 instances of separator_char. musicians[0], with a field width of 17, centered. Then, years_played[0] with a field width of 17, centered. musicians[1], with a field width of 17, centered. Then, years_played[1] with a field width of 17, centered. musicians[2], with a field width of 17, centered. Then, years_played[2] with a field width of 17, centered.
Create a list of two vectors (dog, cat, mouse) and (True, True, False) called a.list. Name the vectors “animal” and “pet” respectively in your list. Access all the elements in the first vector of the list by name.
(1) Prompt the user to enter four numbers, each corresponding to a person's weight in pounds. Store all weights in a list. Output the list. (2 pts) Ex: Enter weight 1: 236.0 Enter weight 2: 89.5 Enter weight 3: 176.0 Enter weight 4: 166.3 Weights: [236.0, 89.5, 176.0, 166.3] (2) Output the average of the list's elements with two digits after the decimal point. Hint: Use a conversion specifier to output with a certain number of digits after the decimal point. (1 pt) (3) Output the max list element with two digits after the decimal point. (1 pt) Ex: Enter weight 1: 236.0 Enter weight 2: 89.5 Enter weight 3: 176.0 Enter weight 4: 166.3 Weights: [236.0, 89.5, 176.0, 166.3] Average weight: 166.95 Max weight: 236.00 (4) Prompt the user for a number between 1 and 4. Output the weight at the user specified location and the corresponding value in kilograms. 1 kilogram is equal to 2.2 pounds. (3 pts) Ex: Enter a list location (1 - 4): 3 Weight in pounds: 176.00 Weight in kilograms: 80.00 (5)…