PART C. Write a program InOrder that reads three integers from the user and prints the three integers in sorted order. For example: Enter three integers, I'11 sort them: 4 7 3 The integers in sorted order are: 3 4 7 When testing your program, you will want to consider other test cases. Hint: What are all the possible input orderings?
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- Write a program that reads from stdin and sorts its input. If no command-line option is given, it should use case-insensitive lexicographic sorting. Ifthe-noption is given, it should use numeric sorting (in this case, you canassume all inputs will be valid integers).I have done this question, but I feel like for some lines, they were supposed to be changed would you be able to help me with that? Consider the following function and attempted body."""from typing import TextIOdef allergy_checker(shopping_lists: TextIO,clean_shopping_lists: TextIO, allergies: list[str]) -> None:'''shopping_lists is a file open for reading that has at least one food name on everynon-blank line. Food names are separated by a space.Each line in shopping_lists ends with a newline character.clean_shopping_lists is a file open for writing.allergies is a list of one-word food names.Copy lines from shopping_lists to clean_shopping_lists.For each food name that is in the allergies list, replace it with 'REMOVED'.If a blank line in shopping_lists is reached, stop reading the file.'''shopping_lists = open(shopping_lists) # Line 1clean_shopping_lists = open(clean_shopping_lists, 'w') # Line 2line = shopping_lists.readline() # Line 3while line.strip(): # Line 4line =…You will be reading in a series of names from the keyboard. Count how many matching pairs there are – a matching pair is when two consecutive names are equal regardless of their case - and print the pairs. Input stops when the word ‘end’ is entered (also ignoring case). For example, Jack Jose jose Faith Robert Cynthia cynthia Cynthia Pierre ENd would print: Jose jose Cynthia cynthia cynthia Cynthia There were 3 matching pairs.
- The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.Write a program called Recursive_fibonacci.java that implements a recursive function for computing the nth term of a Fibonacci Sequence. In the main method of your program accept the value of n from the user as a command-line argument and then call your function named Fibonacci with this value. The output should look exactly like what is pictured below.Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The first integer indicates how many numbers are in the list. Assume that the list will always contain less than 20 integers. Ex: If the input is: 5 10 4 39 12 2 the output is: 2 4 10 12 39 For coding simplicity, follow every output value by a space, including the last one. Your program must define and call the following function. When the SortVector function is complete, the vector passed in as the parameter should be sorted.void SortVector(vector<int>& myVec) #include <iostream>#include <vector>using namespace std; /* Define your function here */ int main() {/* Type your code here */ return 0;} Please help me with this problem using c++.
- Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The first integer indicates how many numbers are in the list. Assume that the list will always contain less than 20 integers. Ex: If the input is: 5 10 4 39 12 2 the output is: 2 4 10 12 39 For coding simplicity, follow every output value by a space, including the last one. Your program must define and call the following function. When the SortVector function is complete, the vector passed in as the parameter should be sorted.void SortVector(vector<int>& myVec) Hint: There are many ways to sort a vector. You are welcome to look up and use any existing algorithm. Some believe the simplest to code is bubble sort: https://en.wikipedia.org/wiki/Bubble_sort. But you are welcome to try others: https://en.wikipedia.org/wiki/Sorting_algorithm. #include <iostream>#include <vector>using namespace std; /* Define your function here */ int main() { /*…Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:1) What are the values of low, high, mid, and target variables?Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:3) If the base case(s) are false, which recursive function call will be made?
- Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:2) Will a base case be true? If so, what value is being returnedGiven is the code to print numbers from 1 to n in increasing order recursively. But it contains few bugs that you need to rectify such that all the test cases pass.Input Format :Integer nOutput Format :Numbers from 1 to n (separated by space)Constraints :1 <= n <= 10000Sample Input 1 : 6Sample Output 1 :1 2 3 4 5 6Sample Input 2 : 4Sample Output 2 :1 2 3 4.This is for Java Write a recursive function that takes as a parameter a nonnegative integerand generates the following pattern of stars. If the nonnegative integer is 4,then the pattern generated is:**********Also, write a program that prompts the user to enter the number of lines inthe pattern and uses the recursive function to generate the pattern. Forexample, specifying 4 as the number of lines generates the above pattern. Java please