Differential Calculus Direction: Differentiate the following trigonometric functions: Part I. 1) y = 10 tan(x) - 2 cot(x) 2) y tan(x) sec(x) 3) y sin (2x) sin(x) 4) y = 6 + 4√x CSC (X) 5) y = x³ - x² sin (x) Part II. Activity #5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Kindly differentiate the part I of this. Thank you!

Differential Calculus
Direction: Differentiate the following trigonometric functions:
Part I.
1) y = 10 tan(x) - 2 cot(x)
2) y tan(x) sec(x)
3) y = sin(2x) sin(x)
4) y = 6 + 4√x csc (x)
5) y = x³ x² sin (x)
Part II.
1) y = cos(2x) sin(x)
2) y sin²(x) cot²(x)
3) y = 2 cos(x) - 6 sec(x) +3
4) y = 3 sec (x)
5) y = 10 cot(x)
Activity #5
Transcribed Image Text:Differential Calculus Direction: Differentiate the following trigonometric functions: Part I. 1) y = 10 tan(x) - 2 cot(x) 2) y tan(x) sec(x) 3) y = sin(2x) sin(x) 4) y = 6 + 4√x csc (x) 5) y = x³ x² sin (x) Part II. 1) y = cos(2x) sin(x) 2) y sin²(x) cot²(x) 3) y = 2 cos(x) - 6 sec(x) +3 4) y = 3 sec (x) 5) y = 10 cot(x) Activity #5
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Follow-up Question

Part II, Number 1 to 3 only =))

Differential Calculus
Direction: Differentiate the following trigonometric functions:
Part I.
1) y = 10 tan(x) - 2 cot(x)
2) y =tan(x) sec(x)
3) y = sin(2x) cos(x)
4) y = 6 + 4√x csc (x)
5) y = x³ - x² sin (x)
Part II.
1) y = cos(2x) sin(x)
2) y sin²(x) cot²(x)
3) y = 2 cos(x) − 6 sec(x) +3
4) y = 3 sec (x)
5) y = 10 cot(x)
Activity #5
Transcribed Image Text:Differential Calculus Direction: Differentiate the following trigonometric functions: Part I. 1) y = 10 tan(x) - 2 cot(x) 2) y =tan(x) sec(x) 3) y = sin(2x) cos(x) 4) y = 6 + 4√x csc (x) 5) y = x³ - x² sin (x) Part II. 1) y = cos(2x) sin(x) 2) y sin²(x) cot²(x) 3) y = 2 cos(x) − 6 sec(x) +3 4) y = 3 sec (x) 5) y = 10 cot(x) Activity #5
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Follow-up Question

Differential Calculus: Part I , Number 3 to 5

Differential Calculus
Direction: Differentiate the following trigonometric functions:
Part I.
1) y = 10 tan(x) - 2 cot(x)
2) y tan(x) sec(x)
3) y = sin(2x) sin(x)
4) y = 6 + 4√x csc (x)
5) y = x³ x² sin (x)
Part II.
1) y = cos(2x) sin(x)
2) y sin²(x) cot²(x)
3) y = 2 cos(x) - 6 sec(x) +3
4) y = 3 sec (x)
5) y = 10 cot(x)
Activity #5
Transcribed Image Text:Differential Calculus Direction: Differentiate the following trigonometric functions: Part I. 1) y = 10 tan(x) - 2 cot(x) 2) y tan(x) sec(x) 3) y = sin(2x) sin(x) 4) y = 6 + 4√x csc (x) 5) y = x³ x² sin (x) Part II. 1) y = cos(2x) sin(x) 2) y sin²(x) cot²(x) 3) y = 2 cos(x) - 6 sec(x) +3 4) y = 3 sec (x) 5) y = 10 cot(x) Activity #5
Solution
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Follow-up Question

Kindly differentiate the part II of this, number 1 to 3. Thank you!

Differential Calculus
Direction: Differentiate the following trigonometric functions:
Part I.
1) y = 10 tan(x) - 2 cot(x)
2) y tan(x) sec(x)
3) y = sin(2x) sin(x)
4) y = 6 + 4√x csc (x)
5) y = x³ x² sin (x)
Part II.
1) y = cos(2x) sin(x)
2) y sin²(x) cot²(x)
3) y = 2 cos(x) - 6 sec(x) +3
4) y = 3 sec (x)
5) y = 10 cot(x)
Activity #5
Transcribed Image Text:Differential Calculus Direction: Differentiate the following trigonometric functions: Part I. 1) y = 10 tan(x) - 2 cot(x) 2) y tan(x) sec(x) 3) y = sin(2x) sin(x) 4) y = 6 + 4√x csc (x) 5) y = x³ x² sin (x) Part II. 1) y = cos(2x) sin(x) 2) y sin²(x) cot²(x) 3) y = 2 cos(x) - 6 sec(x) +3 4) y = 3 sec (x) 5) y = 10 cot(x) Activity #5
Solution
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