Partial fraction decomposition can now be used to write L{y}, such that all terms have linear denominators, which is required to move forward. 2s - 9 A (s - 5)(s + 4) S - 5 s+ 4 2s – 9 = A(s + 4) + B(s – 5) Now, solve for A and B by utilizing the real roots of the denominator, 5 and -4. Doing so gives the following results. A = В 3 Therefore, we have the following. 2s - 9 A B (s - 5)(s + 4) S - 5 s + 4 9 S - 5 s+ 4

Partial fraction decomposition can now be used to write L{y}, such that all terms have linear denominators, which is required to move forward. 2s - 9 A (s - 5)(s + 4) S - 5 s+ 4 2s – 9 = A(s + 4) + B(s – 5) Now, solve for A and B by utilizing the real roots of the denominator, 5 and -4. Doing so gives the following results. A = В 3 Therefore, we have the following. 2s - 9 A B (s - 5)(s + 4) S - 5 s + 4 9 S - 5 s+ 4

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter5: Systems Of Equations And Inequalities

Section5.3: Partial Fractions

Problem 7E

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