5 A multi-cycle instruction performs the two tasks below during one of its cycles. Find the control signals of thiscycle. Use "X' (don't care) when appropriate.PCWriteCondPCSourcePCWriteOutputsALUOPlorDALUSrceMemRendControlALUSrcAMemWriteOp[5-0)MomtoRegRegWriteIRWriteRegDstJumpaddressInstruction (25-0)26Shift28[31-0left 2Instruction(31-26)PC 31-26)Instruction25-21]Readregister 1AddressReaddata 1Instruction(20-16]Readregister 2RegistersWriteregisterZeroALU ALUMemoryMemDataInstruction[15-0ALUOutresultInstruction u[15-11]Readdata 2WritedataInstructionregisterWritedataInstruction[15-0MemorydataSignestendALUcontrolSNR PC + Immediate --> ALUOutB --> Mem[ALUOut]ALUSrcA( Choose )ALUSrcB( Choose )Choose]1ALUOP00 (2-bit)lorD01 (2-bit)MemRead(Choose)MemWrite(Choose )

The solution for the above given question is given below:

Answered: PC + Immediate --> ALUOut B->…

PC + Immediate --> ALUOut B-> Mem[ALUOut] ALUSrcA ( Choose] ALUSrcB [Choose) |Choose ALUOP 00 (2-bit) lorD 01 (2-bit) 3. MemRead [Choose ) MemWrite (Choose )

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Modify below program to include response time Program:SJF CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg;printf("\nEnter the number of processes--"); scanf("%d", &n);for(i=0;i<n;i++){p[i]=i;printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]);}for(i=0;i<n;i++)for(k=i+1;k<n;k++)if(bt[i]>bt[k]){temp=bt[i]; bt[i]=bt[k];bt[k]=temp;temp=p[i];p[i]=p[k];p[k]=temp;}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] =wt[i-1]+bt[i-1];tat[i] =tat[i-1]+bt[i];wtavg = wtavg + wt[i];tatavg = tatavg + tat[i];}printf("\n\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n"); for(i=0;i<n;i++)printf("\n\t P%d \t\t %d \t\t %d \t\t %d", p[i], bt[i], wt[i], tat[i]);printf("\nAverage Waiting Time--%f", wtavg/n);printf("\nAverage Turnaround Time--%f", tatavg/n); getch();}
Modify below program to include response time Program:SJF CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg;printf("\nEnter the number of processes--"); scanf("%d", &n);for(i=0;i<n;i++){p[i]=i;printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]);}for(i=0;i<n;i++)for(k=i+1;k<n;k++)if(bt[i]>bt[k]){temp=bt[i];bt[i]=bt[k];bt[k]=temp;temp=p[i];p[i]=p[k];p[k]=temp;}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0];for(i=1;i<n;i++){wt[i] =wt[i-1]+bt[i-1];tat[i] =tat[i-1]+bt[i];wtavg = wtavg + wt[i];tatavg = tatavg + tat[i];}printf("\n\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++)printf("\n\t P%d \t\t %d \t\t %d \t\t %d", p[i], bt[i], wt[i], tat[i]);printf("\nAverage Waiting Time--%f", wtavg/n);printf("\nAverage Turnaround Time--%f", tatavg/n);getch();}
Examine the following program and find the time delay in seconds. Exclude the overhead due tothe instructions in the loop. MOV TMOD, #10H ; MOV R3 , #200 ;AGAIN: MOV TL1 , # 08H ; MOV TH1, # 01H ; SETB TR1 ;BACK: JNB TF1 ,BACK ; CLR TR ; CLR TF1 ; DJNZ R3 ,AGAIN ;
a. Translate with a three-address statement, the following expression: n = f((x+2), y) – 5; b. If A is an array of integers with width = 4; Translate with three-address statement, the following expression: x = a[i] + 2;
For the DO WHILE AND GOTO loop below, generate an assembly language version of each DO WHILE loop int sumDoWhileLoop(int start, int end) { int sum = 0; int i = start; do { sum += i; i++; } while (i <= end); return sum;} GOTO loop int sumGotoLoop(int start, int end) { int sum = 0; int i = start; loop: sum += i; i++; if (i <= end) goto loop; return sum;} IS THE ASSEMBLY LANGUAGE VERSION OF EACH LOOP THE SAME OR DIFFERENT. COMPARE BASED ON No of registers used, jumps and total no of operations
NASM PROGRAM FOLLOWING THE CODE BELOW, modify it Write an assembly program for the family propcessor x86 in order to transform a temperature from the Celsius scale to the Fahrenheit scale according the transformation below; F=1.8*C +32 Use arithmetic of real numbers for the evaluation of the formula and get the result with two digit of precision in the decimal part. Insert the input by using the keyboard and show the output on the console. section .textglobal mainextern printfextern scanf section .datamessage: db "The temperture in Fahrenheits: %d.", 0msg2: db "%d", 10, 0request: db "Enter a temperature in Celsius: ", 0celsius: times 4 db 0 ; 32-bits integer = 4 bytesreminder: times 4 db 0 formatin: db "%d", 0 main:; Ask for an integerpush requestcall printfadd esp, 4 ; remove the parameter push celsius ; address of integer1, where the input is going to be stored (second parameter)push formatin ; arguments are right to left (first parameter)call scanfadd esp, 8 ;…
The n-th Fibonacci number Fnis defined recursively as Fn=Fn−1+Fn−2 whereF0=0 and F1=1 . For instance, F2=F1+F0=1+0=1 , F3=F2+F1=1+1=2 andF4=F3+F2=2+1=3 . Write an ARM Assembly Language program to compute then-th Fibonacci number Fn. Test your program by computing F15 and F30 .Your progam must write the outputs for the two computations on the screen.
The n-th Fibonacci number Fn is defined recursively as Fn=Fn−1+Fn−2 whereF0=0 and F1=1 . For instance, F2=F1+F0=1+0=1 , F3=F2+F1=1+1=2 andF4=F3+F2=2+1=3 . Write an ARM Assembly Language program to compute then-th Fibonacci number Fn . Test your program by computing F15 and F30 .
Write a single and complete C program to help faculty ‘X’ preparing grades ofEEE 103:a. Ask the user how many students he has in his class and take it as input.b. Dynamically allocate memory and take input of the student’s EEE 103final marks using pointersc. Find the maximum marks obtained among them. The marks must beaccessed using pointer.d. Those who got below 50% of the maximum marks, add 2 marks bonus tothose student’s marks. The marks must be accessed using pointer.e. Consider the final exam has been taken for a total of 45 marks. But theweight of finals for the EEE 103 course is 32%. Now convert eachstudent's marks he received to 32% for preparing the grades. Store theconverted marks in another dynamically allocated array.f. Print the converted marks for all the students.
Perform the given task.
this c++ coding. calculate the total cost and show us step by step the calculation of the total cost using assembly language MIPS. #include <iostream> int main() { int adults; int children; double totaladults; double totalchildren; double total; char option; std::cout << "Welcome to Happy Tour Agency" << std::endl; std::cout << "We have a special rate for 3 days and 2 nights at Langkawi Island,\n" "Pangkor Island, and Tioman Island" << std::endl; std::cout << "Full cost for 3 days for an adult are as follows: " << std::endl; std::cout << "Destination Flight(2 ways) Hotel(3 days)\n" "Langkawi RM 120.00 RM 260.00\n" "Pangkor RM 90.00 RM 330.00\n" "Tioman RM 150.00 RM 390.00" << std::endl; std::cout << "50% discount for each child" << std::endl; std::cout << std::endl; std::cout << "Please enter the number of adults that are going: ";…
Write an ASM program that reads a value for the variable littleEndian and then uses a sequence of MOV instructions to fill the array bigEndian with the bytes of littleEndian in reverse order. For instance, if littleEndian = 12345678h then bigEndian should be filled as 12h, 34h, 56h, 78h. .data bigEndian BYTE ?, ?, ?, ? littleEndian DWORD 12345678h You must first read in an arbitrary value for littleEndian and then fill and display the content of bigEndian in a single line. For example: if I read the value FEDCBA98h for littleEndian, then bigEndian will be first filled and then displayed as FEh, DCh, BAh, 98h. littleEndian must be read as a hexadecimal number; use the readHex library function. Likewise, the cells of bigEndian must be displayed in hexadecimal; use the writeHex library function. Both functions are described in the textbook.