PE Problem for Module 2.1: Solve the complex truss below by the method of substitution. See component reactions at the supports . Match the axial bar force by ticking the circle that corresponds to your answer according to your solution. *

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter5: Three-dimensional Equilibrium
Section: Chapter Questions
Problem 5.26P: The figure shows the FBD of a portion of the space truss shown in Fig. P5.25. Use this FBD to find...
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5.35KN
compression
12.59KN 12.59KN
compression
11.02KN
compression
5.97KN
tension
5.93KN
compression
4.02KN
5.35KN
tension
6.29KN
tension
6.29KN
compression
5.93KN
tension
4.02KN
Compression
11.02KN
5.97KN
tension
tension
compression
tension
bar force on member ab
bar force on member bc
bar force on member cd
bar force on member de
bar force on member ef
bar force on member fa
bar force on member ad
bar force on member be
bar force on member cf
Transcribed Image Text:5.35KN compression 12.59KN 12.59KN compression 11.02KN compression 5.97KN tension 5.93KN compression 4.02KN 5.35KN tension 6.29KN tension 6.29KN compression 5.93KN tension 4.02KN Compression 11.02KN 5.97KN tension tension compression tension bar force on member ab bar force on member bc bar force on member cd bar force on member de bar force on member ef bar force on member fa bar force on member ad bar force on member be bar force on member cf
PE Problem for Module 2.1: Solve the complex truss below by
the method of substitution. See component reactions at the
supports. Match the axial bar force by ticking the circle that
corresponds to your answer according to your solution. *
2m
16KN
4m
16 KN
a
1m
4m
4m
10 KN
10 KN
Transcribed Image Text:PE Problem for Module 2.1: Solve the complex truss below by the method of substitution. See component reactions at the supports. Match the axial bar force by ticking the circle that corresponds to your answer according to your solution. * 2m 16KN 4m 16 KN a 1m 4m 4m 10 KN 10 KN
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