Performing the bitwise XOR operation on A = 000111 and B = 001101 and enter the result. The result must also have a size of 6 bit.
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- We can perform logical operations on strings of bits by considering each pair of corresponding bits separately (called bitwise operation). Given two eight-bit strings A = 10110001 and B = 10101100 , evaluate the eight-bit result after the following logical operations: XORadd x5, x5, x8Every binary digit must be either 0 or 1 or X. If it appears in multiple bits, then you must input multiple bits, e.g.: 0011xx11Control Signal: ValueA random positive integer between 0 and 35767 is generated by the computer. Write aprogram which sets bits 3, 5, 8, 12 and 15 using logical operators only. You are onlyallowed to use 1 bitwise operator. Also, the bitwise operator you are choosing can only beused once. Show the originally generated number and the modified number using 16 bitrepresentation using showbits().
- Assume that D has the value 1010101010 and that the 5-bit generator G=10011 is used. What does R stand for? B. C. Does corruption exist? Publish your work. Repetition of parts a and b with the addition of the following: the numbers 1001010101, 0101101010, and 1010100000CCTT211 Assignment: 1. Change the following decimal numbers to 16-bit two’s complement integersa. -1024b. 16384 2. Change the following 8-bit unsigned numbers to decimala. 11010101b. 00101110 3. If we apply the two’s complement operation to a number twice, we should get the original number. Apply the two’s complement operation to each of the following numbers and see if we can get the original number.a. 110011b. 111111114. Normalize the following binary floating-point numbers. Explicitly show the value of the exponent after normalization.a. 0.1011.1 * 26b. 1101.11 * 2-2 5. Convert the following numbers in 32-bit IEEE format.a. 16.25b. -12.75 6. Convert the following decimal integers to sign-and-magnitude with 8-bit allocationa. 45b. -78 7. One method of representing signed numbers in a computer is one’s complement representation. In this representation, to represent a positive number, we store the binary number. To represent a negative number, we apply the one’s comple- ment operation…Find the result of the bitwise OR expression below, and show it in both hexadecimal and binary formats. Hint: first convert the numbers to binary, perform the OR operation, then convert the binary number to hexadecimal. bis.w 0x80|0x20|0x05|0x01,&P1DIR
- Separate the bit sequence into appropriate sized chuncks for each of the following domains. (You do NOT have to decode this bit sequence.) 1. Octal String: 010 110 101 010 101 111 010 111 111 101 011 011 011 011 010 1001. Hex String:1. Base64 String:In the Hamming coding system (7.3), its representation is expressed as 3 control (test) bits and 7 total bits (data+control bits).In the literature, control bits are represented as (cl, c2, c3, or (pl, p2, p3, .) The bit string sent by encoding with Hamming coding (15,4) is on the receiving side, It is retrieved as 001100101100 (pl.p2.dll). According to this bit sequence;Which option is given according to the control bits (p1.p2.p3.p4) sequence of the received bit sequence?A 0110B 1100C 1001D 0011E 0010You are given two bit locations, I and j, together with the 32-bit values N and M. To insert Minto N, create a method that starts M at bit j and finishes it at bit i. It is safe to presume that all of M can fit in the bits j through i. Therefore, you may infer that there are at least 5 bits between j and I if M = 10011. M could not completely fit between bit 3 and bit 2, thus you would not, for instance, have j = 3 and I = 2.EXAMPLE Key in: NN 10000000000, M 10001001100 as output
- Please do not give solution in image format thanku Present in UTF-8 the 32-bit code given below (in the solution, the byte order from MSB on the left): 11111111 11111111 10110110 11011011 In the solution, separate bytes with a space. If impossible - enter -1Here, A = 0x55. Perform a bitwise operation to clear the 0-3 bits in A.Here, A = 0x73. Perform a bitwise logical operation to set the 1-3 bits in A.Here, A = 0x73. Perform a bitwise logical operation to invert the top four bits of the number and leave the bottom fourbits unchanged.Here is a permutation: location in new byte 1 2 3 4 5 6 7 8 location in source byte 1 3 5 4 2 8 6 7 The source is a byte (8 bits) and the result is a byte (8 bits). Bit numbering starts at one, on the left. If the source byte is 1011 1000 what is the new byte? (Write the answer as 8 characters 0 or 1 with a space in the middle.)