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Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height". Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.

Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height". Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height".Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.
Transcribed Image Text:Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height".Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.
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