Please convert the below pseudocode to a C program.
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Please convert the below pseudocode to a C
![5.
func5 (A,n)
/* A = array of n integers
1 if (n ≤ 30) then return A[1];
2
in-4;
3 x ← A[1];
4 while (i > 3) do
5
6
7
8 end
9 return (x);
A[i] ← A[i] + A[i + 1];
i←i - 6;
xx+ func5(A, i);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e227d4a-60f5-44c4-91bc-6a3c119dc11a%2F7e38b42f-1c9a-424b-9fab-c4f02a1cc08a%2F6schm4y_processed.jpeg&w=3840&q=75)
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- 6. Read in two integers n and m (n, m < 50). Read n integers in an array A. Read m integers in anarray B. Then do the following (write separate programs for each, only the reading part iscommon).a) Find if there are any two elements x, y in A and an element z in B, such that x + y = z.b) Copy in another array C all elements that are in both A and B (intersection).c) Copy in another array C all elements that are in either A and B (union).d) Copy in another array C all elements that are in A but not in B (difference).Do In c ProgramQuestion1. Use recursion [ a. Write a Java method to find the largest element in the array using recursion. public static int largestelement(int[] arr,int n){ } b. Write a Java method to find a target in an array using binary search. (Note the array is sorted descendingly) public static int binarysearch(int[] arr, int target,int l,int r){ } c. Call the methods largestelement() and binarysearch() using the following array a=[13,10,9,8,4,3] and target=10 ANSWER: Output screen capture:(Algebra: perfect square ) Write a program that prompts the user to enter an integer m and find the smallest integer n such that m * n is a perfect square. (Hint: Store all smallest factors of m into an array list. n is the product of the factors that appear an odd number of times in the array list. For example, consider m = 90, store the factors 2, 3, 3, 5 in an array list. 2 and 5 appear an odd number of times in the array list. So, n is 10.) Sample Run 1 Enter an integer m: 1500 The smallest number n for m x n to be a perfect square is 15 m x n is 22500 Sample Run 2 Enter an integer m: 63 The smallest number n for m x n to be a perfect square is 7 m x n is 441 Class Name: Exercise11_17 Answer is : import java.util.Scanner; public class Squares { public static void main(String[] args) { Scanner scan = new Scanner(System.in); //instantiation of Scanner that will take inputs from the keyboard //the try catch block below is for trapping error with the input try {…
- Read in two integers n and m (n, m < 50). Read n integers in an array A. Read m integers in anarray B. Then do the following (write separate programs for each, only the reading part iscommon).a) Find if there are any two elements x, y in A and an element z in B, such that x + y = z.b) Copy in another array C all elements that are in both A and B (intersection).c) Copy in another array C all elements that are in either A and B (union).d) Copy in another array C all elements that are in A but not in B (difference).c programm please tell all the answer(Maximum element in an array) Implement the following method that returns the maximum element in an array . public static > E max (E[] list) Write a test program that prompts the user to enter 10 integers, invokes this method to find the max. Sample Run Enter 10 integers: 3 4 12 7 3 4 5 6 4 7 The max number is 12Java Quick Sort but make it read the data 10, 7, 8, 9, 1, 5 from a file not an array // Java implementation of QuickSort import java.io.*; class GFG { // A utility function to swap two elements static void swap(int[] arr, int i, int j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } /* This function takes last element as pivot, places the pivot element at its correct position in sorted array, and places all smaller (smaller than pivot) to left of pivot and all greater elements to right of pivot */ static int partition(int[] arr, int low, int high) { // pivot int pivot = arr[high]; // Index of smaller element and // indicates the right position // of pivot found so far int i = (low - 1); for (int j = low; j <= high - 1; j++) { // If current element is smaller // than the pivot if…
- using java programming int a[] = {5,10,4,20,1,7}; 1- search for the smallest element in array 2-if you found the smallest element in the array :swap the first element with the smallest elementSingle number (use XOR): Given a non-empty array of integers nums, every element appears twice except for one. Find that single one. You must implement a solution with a linear runtime complexity and use only constant extra space. Code in Java A brief explanation of how and why your code works and how it relates to the concepts learned (for example, it uses bitwise operation, stack, or takes into account a word size).Find a duplicate (20 points). Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where each value is between is 1 and n, and displays true if there are any duplicate values, false otherwise. java FindDuplicate 2 10 8 5 4 1 3 6 7 9 false java FindDuplicate 4 5 2 1 2 true
- Q1. Write the code necessary to find the largest element in an unsorted array of integers. What is the time complexity of this algorithm? Q2. Determine the growth function and order of the following code fragment: for (int count=0; count < n; count++) { for (int count2=0; count2 < n; count2=count2+2) { System.out.println(count, count2); } } Q3. Determine the growth function and order of the following code fragment: for (int count=0; count < n; count++) { for (int count2=0; count2 < n; count2=count2*2) { System.out.println(count, count2); } } Q4. What is the order of the following growth functions? 10n2 + 100n + 1000 10n3 – 7 2n + 100n3 n2 log n Q5. Arrange the growth functions of Q4 in ascending order of efficiency for n=10 and again for n = 1,000,000.java: // Class to do MergeSort and QuickSort on int arrays and test them public class MergeQuickSorts { // Create a main to test MergeSort and QuickSort for // three cases - Sorted Aray, Reverse Sorted Array, Random Array // Each array should be size 50 // For the sorted array use the entries 1, 2, 3......50 // For the reverse sorted array use the entries 50, 49, 48.....1 // For the random array use ints between 1 and 50 inclusive, duplicates allowed // For each of the 6 sorts print the array before and after the sort // and show clearly which sort is being done public static void main(String[] args) { }Complete the following function definition to recursively print the index of a unique value in an array or -1 if the value is not found:1 int getIndex(int *a, int s, int v) {2 if( ) { // if no values are found3 4 }5 if(a[s-1] == v) { // if a value is found6 7 }8 return getIndex( ); // recurse to check next value9 }Hint:Recurse through the array by counting down from size. 1. Complete the one line of code for line 2:2. Write one line of code for line 3:3. Write one line of code for line 6:4. Complete the one line of code for line 8: please send an atom code. not other software
