please help IS TAN 2 ( D ) = SEC 2 ( D ) – [ COS 2 ( D ) + SIN 2 ( D ) ] ? WHY?
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please help
IS TAN 2 ( D ) = SEC 2 ( D ) – [ COS 2 ( D ) + SIN 2 ( D ) ] ? WHY?
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- I have to solve on [0,2π) sinx(tan(x/2))-sinx=0 tytyI don't understand why it gives 2(1/v1 - sinθ/v2) z1/cosθ + x/v2 If someone can help me please.How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read it