Answered: Please realize the following functions…

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter12: Adding Functionality To Your Classes

Section: Chapter Questions

Problem 1PP

See similar textbooks

Please realize the following functions with operator overloading:

input and output time with >> and <<
use += and -= increase and decrease the time ，e.g.Time& operator+=(const Time&);Time& operator-=(const Time&)；

【Input】

There are two line, each line is the time of a clock
Input format：hour minute second。

【Output】

There are two lines.
The first line is the output of time1 += (time2) ;
The second line is the output of time1 -= time2 ;
Output format：hour:minute:second；
Please read the

【Input example】

21 10 35

10 15 25

【Output example】

07:26:00

21:10:34

THE SOLUTION YOU SENT ME IS NOT GIVING THE REQUIRED OUTPUTS. PLEASE LOOK AND READ THE INPUT AND THE OUTPUT SAMPLES ABOVE CAREFULLY.

BELOW IS THE SLOTION YOU GAVE ME.

#include<iostream>

using namespace std;

class Time

{

inthour;

intminute;

intsecond;

public:

Time(){}

Time(int h,int m,int s)

{

hour=h;

minute=m;

second=s;

}

friendistream&operator >>(istream&in,Time&t)

{

in>>t.hour>>t.minute>>t.second;

return in;

}

friendostream&operator<<(ostream&out, Time&t)

{

out<<t.hour<<":"<<t.minute<<":"<<t.second<<endl;

return out;

}

Timeoperator+(constTime&t1)

{

TimeT;

T.second=t1.second+second;

T.minute=t1.minute+minute;

T.hour=t1.hour+hour;

if(T.second>59)

{

T.second=T.second-60;

T.minute=T.minute+1;

}

if(T.minute>59)

{

T.minute=T.minute-60;

T.hour=T.hour+1;

}

if(T.hour>23)

T.hour=T.hour%24;

returnT;

}

Timeoperator-(constTime&t2)

{

Timediff;

if(t2.second>second){

--minute;

second+=60;

}

second=second-t2.second;

if(t2.minute>minute) {

--hour;

minute+=60;

}

minute=minute-t2.minute;

diff.hour=hour-t2.hour;

if(diff.hour<0)

diff.hour+=24;

returndiff;

}

};

int main(){

Timetime1,time2,sum, diff;

cin>>time1;

cin>>time2;

sum=time1+time2;

diff=time1-time2;

cout<<sum<<endl<<diff<<endl;

}

Expert Solution

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Please realize the following functions with operator overloading: input and output time with >> and << use += and -= increase and decrease the time ，e.g.Time& operator+=(const Time&);Time& operator-=(const Time&)；

Please realize the following functions with operator overloading: