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- Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim h→0 7(x + h)2 − 7x2 hEvaluate the limit based on the limit theorems. Give your step by step solution. 1. lim 3x(x+5)= x➪41a. Evaluate the limit using the appropriate properties of limits. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x-> -∞ \sqrt((16x^3+5x-6)/(3-8x+x^3)) ***the whole fraction is squarerooted 1b. Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim-> ∞ (-3/4x+7)
- Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x→−1/2 6x − 8 8x2 + 6Using the graph to evaluate the limitUse properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x→2 f(x), where f(x) = 12 − 2x if x < 2 x2 − x if x ≥ 2
- How do I solve this problem below? I am currently researching limits in Calculus. Evaluate the Limit if it exists? lim x→25 5 − x 25x − x2 and lim h→0 (3 + h)3 − 27 hStruggling to understand how to find the limit as x approches -12 in the following equation.use the graph to find the limit (if it exist). If the limit does not exist explain why this is a calculus problem the equation and graph are ona separate attachment
- How do I find a limit in terms of constant a? lim ((2/a+h)-(2/a)) / h h->0Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x→−1 f(x), where f(x) = x2 + 8 x if x ≤ −1 5x3 − x − 3 if x > −1Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) g(x) = −2x x − 2 (a) lim x→2 g(x) L = The limit does not exist at x = 2 because the function does not approach f(2) as x approaches 2.The limit does not exist at x = 2 because the function is not continuous at any x value. The limit does not exist at x = 2 because f(2) ≠ 2.The limit does not exist at x = 2 because the function increases and decreases without bound as x approaches 2.The limit exists at x = 2. (b) lim x→0 g(x) L = The limit does not exist at x = 0 because the function does not approach f(0) as x approaches 0.The limit does not exist at x = 0 because the function is not continuous at any x value. The limit does not exist at x = 0 because f(0) ≠ 0.The limit does not exist at x = 0 because the function increases and decreases without bound as x approaches 0.The limit exists at x = 0.