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➡pose m and n are constants and m ‡n. Evaluate sin(mx) cos(nx) dx` 1 -cos(m-n)x- -cos(m+n)x] + C n-m -cos(m-n)x+· - -cos(m+n)x+C m-n m+n + n)x] + C m+n) x] + C -sin(m (m_n)x+₁ -sin(m + m-n m+n —cos(m-n)x-. = cos(m+n)x] + C m-n m+n m+n

➡pose m and n are constants and m ‡n. Evaluate sin(mx) cos(nx) dx` 1 -cos(m-n)x- -cos(m+n)x] + C n-m -cos(m-n)x+· - -cos(m+n)x+C m-n m+n + n)x] + C m+n) x] + C -sin(m (m_n)x+₁ -sin(m + m-n m+n —cos(m-n)x-. = cos(m+n)x] + C m-n m+n m+n

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
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Suppose m and n are constants and m # n Evaluate sin(mx) cos(nx) dx 1 -cos(m-n)x- -cos(m+n)x+C 2 n-m m+n 1 -cos(m− n)x+ -cos(m+n)x+C (n)x] + C n) x ] + C m+n)x] + C 2 m-n m+n -sin(m-n)x+ -sin(m+n) m-n m+n 1 —cos(m-n)x- = cos(m+n)x] + C 2 m-n m+n
Transcribed Image Text:Suppose m and n are constants and m # n Evaluate sin(mx) cos(nx) dx 1 -cos(m-n)x- -cos(m+n)x+C 2 n-m m+n 1 -cos(m− n)x+ -cos(m+n)x+C (n)x] + C n) x ] + C m+n)x] + C 2 m-n m+n -sin(m-n)x+ -sin(m+n) m-n m+n 1 —cos(m-n)x- = cos(m+n)x] + C 2 m-n m+n
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