Preconditions: a fix A = [a0;a1,--- , an=1].natural n(length of the arrangement) and a natural m. Post-conditions: the array contains a permutation of the original values such that all elements appear first in A less than m, followed by all elements in A equal to m, and ending with all the elements in A older than m. TIERSORT(A, n, m) 1: i = 0 2: j = 0 3: k = n -1 4: while j <= k do 5: if Alj] > m then aur = A[j] AL = A[k] A[k] = aur 6: 7: 8: 9: k-- else if Alj] = m then j++ else 10: 11: 12: aur = A[i] A[i] = Alj] AG] = aur 13: 14: 15: 16: i++ j++ 18: end if 19: end while 17: a) Show that TierSort That's right. b) Determine the complexity of TierSort in the best and worst case.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Preconditions: a fix A = [da0,a1,…..,an-1], natural n (length of the arrangement) and a
natural m.
Post-conditions: the array contains a permutation of the original values such that all
elements appear first in A less than m, followed by all elements in A equal to m, and
ending with all the elements in A older than m.
TIERSORT(A, n, m)
1: i = 0
2: j = 0
3: k =n - 1
4: while j <= k do
if A[j] > m then
aur = A[i)
Ali] = A[k]
A[k = aux
5:
6:
7:
8:
9:
k--
else if A[j] = m then
j++
else
10:
11:
12:
A[i]
A[i] = Alj]
A[j] = aux
13:
aur =
14:
%3D
15:
16:
i++
j++
end if
17:
18:
19: end while
a) Show that TierSort That's right.
b) Determine the complexity of TierSort in the best and worst case.
Transcribed Image Text:Preconditions: a fix A = [da0,a1,…..,an-1], natural n (length of the arrangement) and a natural m. Post-conditions: the array contains a permutation of the original values such that all elements appear first in A less than m, followed by all elements in A equal to m, and ending with all the elements in A older than m. TIERSORT(A, n, m) 1: i = 0 2: j = 0 3: k =n - 1 4: while j <= k do if A[j] > m then aur = A[i) Ali] = A[k] A[k = aux 5: 6: 7: 8: 9: k-- else if A[j] = m then j++ else 10: 11: 12: A[i] A[i] = Alj] A[j] = aux 13: aur = 14: %3D 15: 16: i++ j++ end if 17: 18: 19: end while a) Show that TierSort That's right. b) Determine the complexity of TierSort in the best and worst case.
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