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Predict the ArH° 298 for the reaction: n-C6H₁14 (1) + CH4 (g) →n - C7H16 (1) + H₂(g) Given the enthalpy of combustion, ACHO 298 (kJ mol-1) = -4,141.3, -882.0, -4,811.2 and -286.1 for n-C6H14, CH4, n - C7H16, H2, respectively. O-74.0 kJ O-30.78 kJ O 30.78 kJ O 74.0 kJ

Predict the ArH° 298 for the reaction: n-C6H₁14 (1) + CH4 (g) →n - C7H16 (1) + H₂(g) Given the enthalpy of combustion, ACHO 298 (kJ mol-1) = -4,141.3, -882.0, -4,811.2 and -286.1 for n-C6H14, CH4, n - C7H16, H2, respectively. O-74.0 kJ O-30.78 kJ O 30.78 kJ O 74.0 kJ

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Predict the ArHO 298 for the reaction: n-C6H14 + CH4 (g) →n - C7H16 (1) + H₂(g) Given the enthalpy of combustion, AcH° 298 (kJ mol-¹) = -4,141.3, -882.0, -4,811.2 and -286.1 for n-C6H₁4, CH4, n – C7H16, H2, respectively. O - 74.0 kJ O - 30.78 kJ 30.78 kJ O 74.0 kJ
Transcribed Image Text:Predict the ArHO 298 for the reaction: n-C6H14 + CH4 (g) →n - C7H16 (1) + H₂(g) Given the enthalpy of combustion, AcH° 298 (kJ mol-¹) = -4,141.3, -882.0, -4,811.2 and -286.1 for n-C6H₁4, CH4, n – C7H16, H2, respectively. O - 74.0 kJ O - 30.78 kJ 30.78 kJ O 74.0 kJ
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