队司MGQ301LRA:Stat Decisions in Mgt:222111336MODULE 4 - Weeks 11 & 12- ANOVA TESTINGWEEK 11 HMWKUsing MS Excel, run the independent-measures single-factor ANOVA for this severety ofdepression data:LowHighModeratelyModerateModerateSevereSevere0.53.32.70.72.3.442.80.81.85.11.31.1.71.24.62.80.52.63.41.6Fill in the summary table for the ANOVA test(Round answers for SS and MS to 3 decimal places.)S.S.M.S.BetweenWithinTOTALAlso from Excel, obtain the necessary statistics for the ANOVA test:(Report P-value & F-ratio accurate to 3 decimal places.)F-ratio:p-value:What is your final conclusion? Use a significance level of a = 0.05.O Reject Ho. There is a significant difference between treatments. At least one of the treatmentsis different.O Do not reject Ho. These data do not provide evidence of a difference between the treatments.Therefore, all treatments are the same (equal).O Do not reject Ho. These data do not provide evidence of a difference between the treatments.PrivTernMacBook AirDD0品F3ofF4F5F2F1&2#24293.4.

The level of significance as 0.05.

Answered: 队司 MGQ301LRA:Stat Decisions in…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In a two-way ANOVA, the main effect of a factor is the A. extent to which the factor produces dependent variable scores different from those the other factor produced. B. effect that changing the levels of the factor has on the dependent variable, taking into account all other factors in the study. C. effect that changing the levels of the factor has on the dependent variable, ignoring all other factors in the study. D. extent to which its effect depends on the other factor.
What source of variation is found in an ANOVA summary table for a within subjects design that is not in an ANOVA summary table for a between subjects design. What happens to this source of variation in a between-subjects design?
Are low-fat diets or low-carb diets more effective for weight loss? This question was addressed in the article “Comparison of the Atkins, Zone, Ornish, and LEARN Diets for Change in Weight and Related Risk Factors Among Overweight Premenopausal Women: The A TO Z Weight Loss Study: A Randomized Trial” (C. Gardner, A. Kiazand, et al., Journal of the American Medical Association, 2007:969–977). A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time the sample mean weight loss was 4.7 kg with a sample standard deviation of 7.2 kg. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kg with a standard deviation of 5.9 kg. a) Can you conclude that the mean weight loss is greater for those on the low-carbohydrate diet? b) Can you conclude that the mean weight loss on the low-carbohydrate diet is more than 1 kg greater than that of the low-fat diet?
Consider a two-way ANOVA with three levels for factor A, three levels for factor B, and four replicates in each of the 9 cells, with SSA=90, SSB=90, SSE=135, and SST=475. Complete parts (a) through (c). A) What is the P-Value? B) At the 0.05 level of significance, is there an effect due to factor A? State the result of this test.
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A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel—emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 A 17 25 31 14 14 24 34 13 B 15 22 28 9 12 19 31 10 C 21 29 32 15 24 28 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21.500000 1 17.166667 B 18.250000 2 24.500000 C 25.625000 3 32.166667 4 13.333333 Analysis of Variance Source DF Sum of Squares Mean Square F Ratio Model 11 1482.4583 134.769 32.6713 Error 12 49.5000 4.125 Prob > F C. Total 23 1531.9583…
A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel—emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 A 17 25 31 14 14 24 34 13 B 16 22 28 9 12 19 31 10 C 21 29 32 15 24 28 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21.500000 1 17.166670 B 18.375000 2 24.500000 C 25.625000 3 32.166670 4 13.500000 Analysis of Variance Source DF Sum of Squares Mean Square F Ratio Model 11 1,458.3333 132.576 32.4675 Error 12 49.0000 4.083 Prob > F C. Total 23 1,507.3333…
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Does St. John wort (an herb) have a siginifact effect in treating major depression? A study looked at 340 adult outpatients suffering as measured by their HAM-Dscore, randomly assiging each subject to either a placebo, St.John's wort, or a second active treatment for comparison. The study found the diiference in treating major depression as measured by improvement in HAM-D scores between St.John's wort and the placebo was not statistically significant This means that: A. a difference this big could easily occur just by chance even if St. John's wort does not better than the placebo B. We cannot make a 95 percent confidence statement C.The placebo makes no difference in the subjects' depression D. The study was badly designed
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Using MS Excel, run the independent-measures single-factor ANOVA for this severety of depression data: LowModerate HighModerate ModeratelySevere Severe 2.1 0.2 1.3 1.8 0.6 1.7 3.9 4.6 1.2 1.5 2.6 2.5 1.7 0.9 3.8 3.8 3 1.8 2.4 4.2 3.1 3.6 2.7 3.8 Fill in the summary table for the ANOVA test(Round answers for SS and MS to 3 decimal places.) S.S. d.f. M.S. Between Within TOTAL Also from Excel, obtain the necessary statistics for the ANOVA test:(Report P-value & F-ratio accurate to 3 decimal places.)F-ratio:  p-value:

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